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kozerog [31]
2 years ago
10

Which would be a biotic factor in an ecosystem? 1)air 2)rain 3)algae

Chemistry
2 answers:
laila [671]2 years ago
7 0
Air and rain are very important
Mars2501 [29]2 years ago
5 0

Answer:

3

Explanation:

because biotic are things you can touch

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Which term describes the information that a scientist gathers during an investigation? Data, hypothesis, observation, variable a
rosijanka [135]

Answer:hypothesis

Explanation:

4 0
3 years ago
A pharmacist wishes to strengthen a mixture from 10%alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of
Tomtit [17]

Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

  • n_{old}=7 litres
  • n_{new}=7+x litres

Also the quantity of alcohol is given as

  • q_{old}=10 \% \, of \, 7 \, litres =0.7
  • q_{added}=x
  • q_{new}= 30 \% \,of \,new\, quantity = 0.3(7+x)

Now the equation is as

                                  q_{old}+q_{added}=q_{new}\\0.7+x=0.3(7+x)\\0.7+x=2.1+0.3x\\x-0.3x=2.1-0.7\\0.7x=1.4\\x=2 \, litres

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

8 0
3 years ago
How many liters of a 4.0 M CaCl2 solution would contain 2 moles of CaCl2?
nekit [7.7K]

Answer:

The answer to your question is 0.5 liters

Explanation:

Data

[CaCl₂] = 4.0 M

number of moles = 2

volume = ?

Process

To solve this problem use the formula of Molarity and solve it for volume, substitute the values and simplify.

-Formula

Molarity = moles / volume

-Solve for volume

Volume = moles / molarity

-Substitution

Volume = 2/4

-Simplification

Volume = 0.5 liters.

5 0
3 years ago
Please help me with these two
Anna [14]
They exist in the outer orbitals
3 0
2 years ago
Convert 400g of phosphoric acid to moles.
Katarina [22]

Answer: 4.08183 or you can round it to 4

Explanation:

3 0
3 years ago
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