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2 years ago

How does air bubbles affect density of a solid object?

1 answer:

6 0

it decreases the density of the object the air bubbles take up space. it increases the volume of the object slightly but the objects weight remains the same, hence the objects density decreases

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A 5.000 g mixture contains strontium nitrate and potassium bromide. Excess lead(II) nitrate solution is added to precipitate out

scZoUnD [109]

Answer: The mass percent of potassium bromide in the mixture is 9.996%

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For lead (II) bromide:

Given mass of lead (II) bromide = 0.7822 g

Molar mass of lead (II) bromide = 367 g/mol

Putting values in equation 1, we get:

$\text{Moles of lead (II) bromide}=\frac{0.7822g}{367g/mol}=0.0021mol$

The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:

$2KBr+Pb(NO_3)_2\rightarrow PbBr_2+2KNO_3$

By Stoichiometry of the reaction:

1 mole of lead (II) bromide is produced from 2 moles of potassium bromide

So, 0.0021 moles of lead (II) bromide will be produced from = $\frac{2}{1}\times 0.0021=0.0042mol$ of potassium bromide

Now, calculating the mass of potassium bromide by using equation 1, we get:

Molar mass of KBr = 119 g/mol

Moles of KBr = 0.0042 moles

Putting values in equation 1, we get:

$0.0042mol=\frac{\text{Mass of KBr}}{119g/mol}\\\\\text{Mass of KBr}=0.4998g$

To calculate the percentage composition of KBr in the mixture, we use the equation:

$\%\text{ composition of KBr}=\frac{\text{Mass of KBr}}{\text{Mass of mixture}}\times 100$

Mass of mixture = 5.000 g

Mass of KBr = 0.4998 g

Putting values in above equation, we get:

$\%\text{ composition of KBr}=\frac{0.4998g}{5.000g}\times 100=9.996\%$

Hence, the percent by mass of KBr in the mixture is 9.996 %

5 0

3 years ago

A mixture of lipids is applied to a silica gel column, and the column is then washed with increasingly polar solvents. the mixtu

Ket [755]

YOu need some fresh memes sir

6 0

2 years ago

What type of reaction is shown below? a) Addition reaction b) Esterification

Gemiola [76]

Answer:

a) Addition reaction, is your answer

6 0

2 years ago

Describe how surface currents would be effective Earth did not rotate

kicyunya [14]

The moon is what makes currents so if there was no moon there would be no current in our oceans. The way it makes currents is from the gravitational pull.
Brainliest? :)

3 0

3 years ago

How many grams of oxygen are required too burn 8.8g of c3h8?

hichkok12 [17]

From the balanced equation:
1mol C3H8 requires 5mol O2 for combustion 
Molar mass C3H8 = 44g/mol 
8.8g C3H8 = 8.8/44 = 0.2mol C3H8 
This will require 5*0.2 = 1.0mol O2 
Molar mass O2 = 32g/mol 
Therefore 32g of O2 required.

4 0

3 years ago