I think this is what you're after:
Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]
Convert to J and divide by the Avogadro Const to give E in J per photon
E = 375700/6.022×10^23 = 6.239×10^-19 J
Plank relationship E = h×ν E in J ν = frequency (Hz s-1)
Planck constant h = 6.626×10^-34 J s
6.239×10^-19 = (6.626×10^-34)ν
ν = 9.42×10^14 s^-1 (Hz)
IP are usually given in ev Cs 3.894 eV
<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>
Is it250 degrees c if so it would be <span> 4.66 moles</span>
1.40E+5 (140000)
I believe this is right
Answer:
None of the options are correct
Explanation:
Ketone is an organic compound with general formula RCOR' ie RC=OR where R and R' are alkyl groups. Example of ketone can be written as:
C—C—C=O—C
