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3 years ago

3. How much heat (in joules) is needed to raise the temperature of 355 g of ethanol I

Chemistry

1 answer:

Rudiy273 years ago

6 0

Answer:

53676 J

Explanation:

m = 355 g

c = 2.4 J/gºC

ΔT = 63°C

q = mcΔT

= (355)(2.4)(63)

= 53676 J

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Na+H2O=NaOH+H2 Balancing

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Answer:

Hey mate, here is your answer. Hope it helps you.

Explanation:

The balanced equation is 2Na+2H2O———-> 2NaOH +H2.

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3 years ago

How much mass defect is required to release 5.5 x 1020 J of energy?

Montano1993 [528]

Answer : The mass defect required to release energy is 6111.111 kg

Explanation :

To calculate the mass defect for given energy released, we use Einstein's equation:

$E=\Delta mc^2$

E = Energy released = $5.5\times 10^{20}J$

$\Delta m$ = mass change = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in above equation, we get:

$5.5\times 10^{20}Kgm^2/s^2=\Delta m\times (3\times 10^8m/s)^2$

$\Delta m=6111.111kg$

Therefore, the mass defect required to release energy is 6111.111 kg

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3 years ago

Based on these data, what is the average atomic mass of element b? 10.01 10.51 10.81 11.01

Lelechka [254]

The right answer is C. 10.81

5 0

3 years ago

Read 2 more answers

How many Joules are released to cool 250.0 grams of liquid water from 100°C to 0°C? The specific heat of water is 4.180 J/g.C.

nlexa [21]

$\bold{\huge{\orange{\underline{ Solution}}}}$

$\bold{\underline{ Given :- }}$

We have 250g of liquid water and it needs to be cool at temperature from 100° C to 0° C
Specific heat of water is 4.180J/g°C

$\bold{\underline{ To \: Find :- }}$

We have to find the total number of joules released.

$\bold{\underline{ Let's \:Begin:- }}$

We know that,

Amount of heat energy = mass * specific heat * change in temperature

That is, 

$\sf{\red{ Q = mcΔT }}$

Subsitute the required values in the above formula :-

$\sf{ Q = 250 × 4.180 ×(0 - 100 )}$

$\sf{ Q = 250 × 4.180 × - 100 }$

$\sf{ Q = 250 × - 418}$

$\sf{\pink{ Q = - 104,500 J }}$

Hence, 104,500 J of heat is released to cool 250 grams of liquid water from 100° C to 0° C.

$\bold{\underline{ Now :- }}$

We have to tell whether the above process is endothermic or exothermic :-

Here, In the above process ΔT is negative and as a result of it Q is also negative that means above process is Exothermic

Exothermic process :- It is the process in which heat is evolved .
Endothermic process :- It is the process in which heat is absorbed .

4 0

2 years ago

Question 2

Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0

3 years ago