Answer:
3000N
Explanation:
divided to get answer
the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
Answer:
A = 2,8333 s
Explanation:
El periodo es definido como el tiene que toma de dar una oscilación.
En este caso realiza varias osicilacion por lo cual debemos encontrar el promedio del perdono.
T = t/n
calculemos
A = 34,0/ 12,0
A = 2,8333 s
True: Friction depends on the types of surfaces involved and how hard the surfaces push together.
Answer:
Are you trying to calculate the net force?
If so, it would be 3 N Up.
This is because the 15 N forces from the left and right cancel out, leaving only the upwards 15 N force, and the 12 N force. However, we have to subtract 12 from 15, leaving the final net force to be 3 N Up.
Let me know if this helps!
I think the answer would be C. G<span>ravitational force is proportional to the square of the distance between the centers of both bodies. </span>
