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Ne4ueva [31]
3 years ago
5

Identify two size dependent properties and two size independent properties of an iron nail

Physics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0

2 size dependent = volume and mass. 2 size independent properties = conductivity, bowing point, state of matter, and melting point. analyze, name two size dependent properties and two size independent properties of an iron nail.


hope this helps

Lena [83]3 years ago
3 0

dependent volume and mass and independent melting point and bowing point

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There are three things needed to be classified as a planet.

Pluto meets 2 of the 3.

The one it does not meet is it doesn’t “clear the neighborhood” which means a planet needs to be gravitationally dominant over all objects around it. Meaning smaller bodies ( asteroids) would either combine with the larger body making it bigger or pushing them away ( out of their orbit) so they do not collide with the larger body.

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1 hr 16 minutes equal how many minutes ?​
Len [333]

Answer:

76 minutes.

Explanation:

There are 60 minutes in an hour + 16 minutes= 76 minutes.

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3 years ago
Para fabricar la bicicleta de un niño pequeño se tiene en cuenta que la fuerza que puede desarrollar es menor que la de un adult
Georgia [21]

Answer:

a) El piñón debe tener 20 dientes.

b) La bicicleta avanza aproximadamente 1,759 metros por cada pedaleada completa.

Explanation:

a) El plato es el engranaje más grande que forma parte del sistema de transmisión, acompañando a la cadena y el piñón integrado a la rueda trasera. Asumiendo que no existen pérdidas por fricción seca y que las condiciones de lubricación del sistema de transmisión son óptimas tal que las pérdidas de potencia son despreciables. Además, supongamos que la bicicleta viaja a velocidad constante, entonces tenemos la siguiente identidad mediante las definiciones de trabajo y potencia:

T_{P}\cdot \omega_{P} = T_{p}\cdot \omega_{p} (1)

Donde:

T_{P} - Torque del plato, en newton-metros.

T_{p} - Torque del piñón, en newton-metros.

\omega_{p} - Rapidez angular del piñón, en radianes por segundo.

\omega_{P} - Rapidez angular del plato, en radianes por segundo.

Sabiendo el hecho que tanto el plato y el piñón experimenta la misma velocidad tangencial, podemos simplificar (1) como sigue:

\frac{T_{P}}{R_{P}} = \frac{T_{p}}{R_{p}} (1b)

Puesto que el radio de cada elemento y el número de dientes son, por separado, directamente proporcionales al número de dientes, modificamos (1b) así y tenemos la siguiente identidad, la cual equivale a su vez a la razón de desarrollo:

\frac{T_{P}}{T_{p}} = \frac{N_{P}}{N_{p}} = \frac{R_{P}}{R_{p}} = \frac{\omega_{p}}{\omega_{P}} (1c)

Donde:

N_{p} - Número de dientes del piñón, sin unidad.

N_{P} - Número de dientes del plato, sin unidad.

Si tenemos que r = 1,4 y N_{P} = 28, entonces tenemos que el número de dientes del piñón es:

r = \frac{N_{P}}{N_{p}}

N_{p} = \frac{N_{P}}{r}

N_{p} = \frac{28}{1,4}

N_{p} = 20

El piñón debe tener 20 dientes.

b) De acuerdo con la relación de desarrollo, por cada revolución realizada por el plato, el piñón realiza 1,4 revoluciones. Entonces, el avance realizado por la rueda trasera (s), en metros, es igual al productor de la relación de desarrollo y la circunferencia de la rueda, es decir:

s = r\cdot 2\pi\cdot R (1)

Donde R es el radio de la rueda trasera, en metros.

Si conocemos que r = 1,4 y R = 0,2\,m, entonces el avance realizado por la rueda trasera es:

s = r\cdot 2\pi\cdot R

s = (1,4)\cdot (2\pi)\cdot (0,2\,m)

s \approx 1,759 \,m

La bicicleta avanza aproximadamente 1,759 metros por cada pedaleada completa.

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3 years ago
How far something moves in a specific amount of time
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Distance is how far something moves in a specific amount of time. 
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3 years ago
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A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude and direction of the net ele
lesya692 [45]

Explanation:

It is given that,

Length of the rod, l = 14 cm = 0.14 m

Charge on the rod, q=-22\ \mu C=-22\times 10^{-6}\ C

We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m

Electric field at the axis of the rod is given by :

E=\dfrac{\lambda}{2\pi \epsilon_o z}

Where

\lambda is the linear charge density of the rod,

\lambda=\dfrac{q}{l}=\dfrac{-22\times 10^{-6}\ C}{0.14\ m}=-0.00015\ C/m

E=\dfrac{-0.00015}{2\pi\times 8.85\times 10^{-12}\times 0.36}

E = -7493170.57 N/C

or

E=-7.49\times 10^6\ N/C

Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.

4 0
3 years ago
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