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MAVERICK [17]
3 years ago
7

Name at least three physical properties of the bowling ball.

Physics
2 answers:
Tatiana [17]3 years ago
6 0
Hey there!

Here is your answers:

<u><em>The proper answers to this question is...</em></u>

<u><em>"1. The bowling ball is round</em></u>
<u><em>2. The bowling ball has 3 holes in the center</em></u>
<u><em>3. The bowling ball has a large mass (meaning its heavier than other balls)"</em></u>

Reason:

<u><em>Remember that the physical properties is meaning to state the physical features of a bowling ball. For example its heavy, there id three holes on it, and its a round shape or a sphere. When you come across questions like this just state the features of that object in order to get your answer!</em></u>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
oksian1 [2.3K]3 years ago
4 0
Density - Describes how compact the matter is in a substance. ...
Color - Describes how light reflects off a substance.
Luster - Describes how shiny a substance is. ...
Texture - Describes the smoothness/roughness of a substance.
Odor - Describes the smell of a substance.
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svetoff [14.1K]

Work done against gravity to climb upwards is always stored in the form of gravitational potential energy

so we can say

W = mgh

here h = vertical height raised

so here we know that

h = 14.1 sin7.3 km

here we have

h = 1.79 km

now from above equation

W = (83 kg)(9.81 m/s^2)(1.79 \times 10^3 m)

W = 1.46 \times 10^6 J

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3 years ago
A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just
bagirrra123 [75]

Answer: C

Frictional force

Explanation:

The description of the question above is an example of a circular motion.

For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.

Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.

Therefore, the correct answer is option C - the frictional force.

5 0
4 years ago
Which of the following displays has the highest hz frequency
Ganezh [65]

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What prevents the pressure from increasing as a cloud contracts due to its gravity?
Vesnalui [34]

Thermal energy is converted to radiative energy via molecular collisions and released as photons.

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3 years ago
A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh
Elanso [62]

Answer:

The value is  v  =  2.3359 *10^{4} \ m/s

Explanation:

From the question we are told that

  The  initial speed is u =  2.05 *10^{4} \  m/s

 Generally the total energy possessed by the space probe when on earth is mathematically represented as

             T__{E}} =  KE__{i}} +  KE__{e}}

Here  KE_i is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

          KE_i =   \frac{1}{2}  *  m  *  u^2

=>       KE_i =   \frac{1}{2}  *  m  *  (2.05 *10^{4})^2

=>       KE_i =  2.101 *10^{8} \ \ m \ \ J

And  KE_e is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

       KE_e =  \frac{1}{2}  *  m *  v_e^2

Here v_e is the escape velocity from earth which has a value v_e =  11.2 *10^{3} \  m/s

=>    KE_e =  \frac{1}{2}  *  m *  (11.3 *10^{3})^2

=>    KE_e =  6.272 *10^{7} \  \  m  \ \   J

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

        KE_p =  \frac{1}{2}  *  m *  v^2

Generally from the law energy conservation we have that

        T__{E}} =  KE_p

So

       2.101 *10^{8}  m  +  6.272 *10^{7}  m  =   \frac{1}{2}  *  m *  v^2

=>     5.4564 *10^{8} =   v^2

=>     v =  \sqrt{5.4564 *10^{8}}

=>     v  =  2.3359 *10^{4} \ m/s

4 0
3 years ago
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