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MAVERICK [17]
3 years ago
7

Name at least three physical properties of the bowling ball.

Physics
2 answers:
Tatiana [17]3 years ago
6 0
Hey there!

Here is your answers:

<u><em>The proper answers to this question is...</em></u>

<u><em>"1. The bowling ball is round</em></u>
<u><em>2. The bowling ball has 3 holes in the center</em></u>
<u><em>3. The bowling ball has a large mass (meaning its heavier than other balls)"</em></u>

Reason:

<u><em>Remember that the physical properties is meaning to state the physical features of a bowling ball. For example its heavy, there id three holes on it, and its a round shape or a sphere. When you come across questions like this just state the features of that object in order to get your answer!</em></u>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
oksian1 [2.3K]3 years ago
4 0
Density - Describes how compact the matter is in a substance. ...
Color - Describes how light reflects off a substance.
Luster - Describes how shiny a substance is. ...
Texture - Describes the smoothness/roughness of a substance.
Odor - Describes the smell of a substance.
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(b) The particle displacement y of air molecules due to a sound wave is given by y 4m and w = = 0.008 cos wt sin kz. Where k - m
serious [3.7K]

The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.

<h3>What's the distance between consecutive nodes of the displacement of air molecules?</h3>
  • Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.
  • So, distance between consecutive nodes = wavelength = 2π÷k

= 2π/(4π÷m)

= m/2

<h3>What's the amplitude after 0.56s of the displacement of air molecules?</h3>

Displacement after 0.56 s = 0.008×cos(50π×0.56s)

=1.75×10^(-4) m

Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.

Calculate:

I) the distance between 2 consecutive nodes

ii) the amplitude after 0.565s

Learn more about the wavelength here:

brainly.com/question/10750459

#SPJ1

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2 years ago
Help me please!! 15points
Romashka-Z-Leto [24]

Explanation:

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a = Δv / Δt

a. The car's acceleration is:

a = (80 km/h − 0 km/h) / 10 s

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So every second, the speed increases by 8 km/h.

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a = (16 m/s − 4.0 m/s) / 5.6 s

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10.0 m/s² = (v − 0 m/s) / 3.5 s

v = 35 m/s

d. The time is:

1.6 m/s² = (10 m/s − 0 m/s) / t

t = 6.3 s

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