The reason the "+ C" is not needed in the antiderivative when evaluating a definite integral is; The C's cancel each other out as desired.
<h3>How to represent Integrals?</h3>
Let us say we want to estimate the definite integral;
I = 
Now, for any C, f(x) + C is an antiderivative of f′(x).
From fundamental theorem of Calculus, we can say that;
where Ф(x) is any antiderivative of f'(x). Thus, Ф(x) = f(x) + C would not work because the C's will cancel each other.
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Functions can be represented using equations, graphs and tables.
The function is given as:
When l = 1, we have:
When l = 2, we have:
When l = 3, we have:
When l = 4, we have:
Represent the above results as a table, we have:
<u>l a(l)</u>
1 0.5
2 2.0
3 4.5
4 8.0
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Answer:
6x+2
Step-by-step explanation:
your combine like terms...
so 13x is teh same as -7x
13x-7x= 6x
3 and -1 are the same as well
3-1=2
so teh answer would be
6x+2
Answer:
5 hours
Step-by-step explanation:
That's true. If the integers both have the same sign, then their product and quotient are both positive. If signs are different, then product and quotient are both negative.
