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Natasha_Volkova [10]
3 years ago
7

Which compounds are lewis acids? select all that apply. (ch3ch2)2hc+ cl3c− ch3nh2 bbr3?

Chemistry
1 answer:
alexandr402 [8]3 years ago
3 0

The Lewis acids are electron pair acceptors due to the availability of vacant orbitals they accept electrons from the donor compounds.

  • (CH_3CH_2)_2CH^{+} is a Lewis acid due to the unfilled valence shell on carbon atom (possessing positive charge) it accepts electron readily.
  • CCl_{3}^{-} is not a Lewis acid due to the presence of negative charge which represents that there are electrons available for donation.
  • CH_3NH_2 is not a Lewis acid due to the presence of lone pair on nitrogen which is easily donated to the acceptors.
  • BBr_3 is a Lewis acid due to the availability of vacant p-orbital on boron atom.

Hence, (CH_3CH_2)_2CH^{+} and BBr_3 are Lewis acids.

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What volume of 1.25 M solution is needed to make 250 mL of 0.75 M solution?
zysi [14]

Answer:

V1= 150ml

Explanation:

C1= 1.25, V1=?, C2= 0.75, V2= 250ml

Applying dilution formula

C1V1= C2V2

V1= (0.75×250)/1.25 = 150ml

6 0
3 years ago
PLEASE HELP!!! A mineral that has no planes of weakness in its lattice structure will not break along straight lines. Which term
nignag [31]
The answer is Cleavage
4 0
3 years ago
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The teacher made a 0.5M solution. How is this number read/said?
lukranit [14]

Answer:

It reads as follows: 0.5 moles of solute per liter of solution.

Explanation:

Molarity is the most frequent way of expressing the concentration of solutions in chemistry, and it indicates the number of moles of solute dissolved per liter of solution; is represented by the letter M.

3 0
3 years ago
What is the molarity of 40ml of NaOH if it takes 25ml of 0.5 molar HCl to neutralize it?
Oksanka [162]

Answer:

Molarity of 40 ml of NaoH is 0.3125 mL

Explanation:

As we know  

Molarity of acid *  volume of acid = molarity of base * volume of base

Substituting the given values, we get  

0.5 * 25 = X* 40 \\X = \frac{0.5*25}{40} \\X = 0.3125

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6 0
3 years ago
Consider the reaction:
Fofino [41]

The mass in grams of NH₃ produced from the reaction is 3.4 g

<h3>Balanced equation</h3>

We'll begin by writing the balanced equation for the reaction. This illustrated below:

N₂ + 3H₂ -> 2NH₃

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

<h3>How to determine the volume of NH₃ produced</h3>

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

Therefore,

2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃

<h3>How to determine the mass of NH₃ produced</h3>

We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:

22.4 dm³ = 1 mole NH₃

Therefore,

4.48 dm³ = 4.48 / 22.4

4.48 dm³ = 0.2 mole of NH₃

Finally, we shall determine the mass of NH₃ as follow:

  • Molar mass of NH₃ = 17 g/mol
  • Mole of NH₃ = 0.2 mole
  • Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 0.2 × 17

Mass of NH₃ = 3.4 g

Learn more about stoichiometry:

brainly.com/question/13196642

#SPJ1

4 0
1 year ago
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