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Natasha_Volkova [10]
3 years ago
7

Which compounds are lewis acids? select all that apply. (ch3ch2)2hc+ cl3c− ch3nh2 bbr3?

Chemistry
1 answer:
alexandr402 [8]3 years ago
3 0

The Lewis acids are electron pair acceptors due to the availability of vacant orbitals they accept electrons from the donor compounds.

  • (CH_3CH_2)_2CH^{+} is a Lewis acid due to the unfilled valence shell on carbon atom (possessing positive charge) it accepts electron readily.
  • CCl_{3}^{-} is not a Lewis acid due to the presence of negative charge which represents that there are electrons available for donation.
  • CH_3NH_2 is not a Lewis acid due to the presence of lone pair on nitrogen which is easily donated to the acceptors.
  • BBr_3 is a Lewis acid due to the availability of vacant p-orbital on boron atom.

Hence, (CH_3CH_2)_2CH^{+} and BBr_3 are Lewis acids.

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2 years ago
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

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Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

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= 30 ml

Molarity of base,

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As we know,

⇒  Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}

On substituting the values, we get

⇒           0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}

⇒  Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}

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hence,

⇒  Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}

On substituting the values, we get

⇒  1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}

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