1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
2 years ago
13

Calcium chloride (aq) reacts with sodium carbonate (aq) to from solid calcium carbonate and aqueous sodium chloride. Determine t

he volume of a 2.00 M Calcium chloride solution would be needed to exactly react with 0.0650 L of 1.50 M Na2CO3. (Use BCA!)
Chemistry
2 answers:
sattari [20]2 years ago
8 0

Answer:

We need a volume of 48.75 mL of CaCl2 to react

Explanation:

Step 1: Data given

Molarity of calcium chloride = 2.00 M

Volume of Na2CO3 = 0.0650 L

Molarity of Na2CO3 = 1.50 M

Step 2: The balanced equation

CaCl2 (aq) + Na2CO3(aq) → CaCO3 + 2NaCl

Step 3: Calcumate moles Na2CO3

Moles Na2CO3 = molarity Na2CO3 * volume

Moles Na2CO3 = 1.50 M * 0.0650 L

Moles Na2CO3 = 0.0975 moles

Step 4: Calculate moles CaCl2 neede to react

For 1 mol CaCl2 we need 1 mol Na2CO3 to produce 1 mol CaCO3 and 2 moles NaCl

For 0.0975 moles Na2CO3 we need 0.0975 moles CaCl2

Step 5: Calculate volume of CaCl2 solution

Volume = moles CaCl2 / molarity CaCl2

Volume = 0.0975 moles / 2.00 M

Volume = 0.04875 L = 48.75 mL

We need a volume of 48.75 mL of CaCl2 to react

natulia [17]2 years ago
4 0

Answer:

0.0488 L

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

CaCl2(aq) + Na2CO3(aq) —> CaCO3(s) + 2NaCl(aq)

Step 2:

Determination of the number of mole of Na2CO3 in 0.0650 L of 1.50 M Na2CO3 solution.

Volume of solution = 0.0650 L

Molarity of Na2CO3 = 1.50 M

Mole of solute (Na2CO3) =?

Molarity = mole of solute /Volume of solution

1.50 = mole of solute/0.0650

Cross multiply to express in linear form.

Mole of solute = 1.5 x 0.0650

Mole of solute (Na2CO3) = 0.0975 mole

Step 3:

Determination of the number of CaCl2 that reacted.

CaCl2(aq) + Na2CO3(aq) —> CaCO3(s) + 2NaCl(aq)

From the balanced equation,

1 mole of CaCl2 reacted with 1 mole Na2CO3.

Therefore, 0.0975 mole of CaCl2 will also react with 0.0975 mole of Na2CO3.

Step 4:

Determination of the volume of CaCl2 that reacted.

Mole of solute (CaCl2) = 0.0975 mole

Molarity of CaCl2 = 2.00 M

Volume of solution =?

Molarity = mole of solute /Volume

2 = 0.0975/volume

Cross multiply to express in linear form

2 x Volume = 0.0975

Divide both side by 2

Volume = 0.0975/2

Volume = 0.0488 L

Therefore, the volume of CaCl2 that is 0.0488 L

You might be interested in
Tell me What is an element?
Anarel [89]

Answer:

Any substance that cannot be decomposed into simpler substances by ordinary chemical processes.

Another definition:

An element is the simplest pure substance which can neither be split nor built up from other simpler substances by chemical reaction

5 0
2 years ago
Will give brainliest
sergiy2304 [10]
It shows the atomic number
8 0
3 years ago
What volume of oxygen (in L) is produced
sveticcg [70]

Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

= 207.2 + 2[14.01 + 48]

= 207.2 + 2[62.01]

= 207.2 + 124.02

= 331.22 g/mol

Mass of Pb(NO₃)₂ = 147.1 g

Mole of Pb(NO₃)₂ =?

Mole = mass / Molar mass

Mole of Pb(NO₃)₂ = 147.1 / 331.22

Mole of Pb(NO₃)₂ = 1.104 moles.

Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.552 mole of O₂ will occupy = 0.552 × 22.4 = 12.36 L at STP.

Thus, the volume of oxygen gas, O₂ produced is 12.36 L.

6 0
2 years ago
Evaporate minerals, or "salts," include halite, anhydrite, and ______.
pav-90 [236]
B is the correct answer! I learned this in class last week :)
5 0
3 years ago
Read 2 more answers
the daily dose of ampicillin for the treatment of an ear infection is 115 mg/kg of body weight. what is the daily dose for a 43-
Lorico [155]
M=43lb = 19,5kg

If 115mg --------- is for --------- 1kg
                             so
    x        ---------- is for --------- 19,5kg

x = 19,5kg * 115mg / 1kg
x = 2242,5 mg
6 0
2 years ago
Read 2 more answers
Other questions:
  • Is au an atomic element, molecular element, molecular compound or an ionic compound?
    14·1 answer
  • The time that is taken by neptune once around the sun is called
    5·1 answer
  • Please HELP I WILL MARK BRAINLY
    11·2 answers
  • Temperature is an example of a categorical variable a quantitative variable either a quantitative or categorical variable neithe
    9·1 answer
  • A chemical reaction gives off 2100 kg of heat energy how many calories
    7·1 answer
  • Select all that apply.
    10·1 answer
  • According to the kinetic-molecular theory of gases, molecules of an ideal gas
    11·1 answer
  • A scientist is measuring the rate of an enzyme-catalyzed reaction that produces a red-colored product. as the solution containin
    15·2 answers
  • What is the symbol for sodium chloride?
    13·1 answer
  • Ammonia and hydrogen fluoride both have unusually high boiling points due to
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!