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Brrunno [24]
3 years ago
9

Moles to Particles

Chemistry
1 answer:
madam [21]3 years ago
6 0

Answer:

There are 2,04x10 e-6 moles of water in 1.23x10e18   molecules

Explanation:

We use Avogadro's number, according to which in 1 mole of any substance there are 6,023 x 10 e23 particles (example: atoms, molecules). We calculate the number of moles according to the following simple three rule:

6,023 x 10 e23 molecules-----1 mol of water

1.23x10e18   molecules----x=

x=(1.23x10e18   molecules x1 mol of water)/6,023 x 10 e23 molecules

<em>x=2,04x10 e-6 moles of water</em>

<em></em>

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ΔH = (-393.5) - (–74.87 + 2*–241.8)

ΔH = 164.97 kJ = 164970 J

ΔS = ∑nΔS(products) - ∑nΔS(reactant)

ΔS = (213.7 + 4*130.7) - (186.1 + 2*188.8)

ΔS = 172.8 J

0 > 164970 J - T* 172.8 J

-164970 J > - T* 172.8 J

954.7< T

The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.

Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.

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A buffer solution is composed of 4.00 4.00 mol of acid and 3.25 3.25 mol of the conjugate base. If the p K a pKa of the acid is
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