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3 years ago

How many newtons of force are represented by the following amount: 3 kg·m/sec^2?

1 answer:

4 0

1 newton is the force that accelerates
1 kilogram of mass at the rate of 1 m/s² .

So in SI base units, 1 newton = 1 kg-m/s² .

and 3 kg-m/s² = 3 newtons .

You might be interested in

In a compression wave, particles in the medium move

nikdorinn [45]

in the same direction as the wave

Explanation:

In a compression wave, the particles in the medium moves in the same direction as the wave source.

A wave is generally defined as a disturbance that transmits energy.

There are two types of waves based on the direction through which they are propagated.
Transverse waves are directed perpendicularly in the direction of propagation.
Examples are electromagnetic waves.
Longitudinal waves are parallel to their source. Examples are sound waves, p-waves.
They are made up of series of rarefaction and compression.

learn more:

Waves brainly.com/question/3183125

#learnwithBrainly

8 0

3 years ago

If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate

pogonyaev

Let h = distance (m) to the water surface.

Initial velocity, u = 0 (because the stone was dropped).
Use the formula
h = ut + (1/2)gt^2
where g = 9.8 m/s^2 (acc. due to graity)
t = time (s)

h = (1/2)*(9.8)*(3^2) = 44.1 m

8 0

3 years ago

A kangaroo jumps to a vertical height of 2.8 m. How long was it in the air before returning to earth

BaLLatris [955]

The answer would be 2.8m height on earth takes
2.8=1/2*9.8*t^2 => <span>s = ut +1/2at^2 </span>

8 0

3 years ago

A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca

love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. $s_{o}$ = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

$v_{i}$ = 33.2 m/s, a = 0 (since the velocity is constant), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

s = 33.2t .......... eq (1)

Hatchback:

$a=5m/s^{2}$ , $v_{i}$ = 0 m/s (since initial velocity is zero), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

putting in the data we will get

$s=(1/2)(5)t^{2}$

now putting 's' value from eq (1)

$2.5t^{2}-33.2t=0$

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

7 0

3 years ago

Read 2 more answers

While riding in a hot air balloon, which is steadily decreasing at a speed of 1.14 m/s, you accidentally drop your cell phone. H

Ilia_Sergeevich [38]

Answer:

The distance covered by the balloon is 47.52 meters.

Explanation:

Given that,

Initial speed of the balloon, u = 1.14 m/

Let us assumed we need to find the distance covered by the balloon after t = 3 second. Let d is the distance covered by the balloon. It can be given by :

$d=ut+\dfrac{1}{2}at^2$

Here, a = g

$d=ut+\dfrac{1}{2}gt^2$

$d=1.14\times 3+\dfrac{1}{2}\times 9.8\times (3)^2$

d = 47.52 meters

So, the distance covered by the balloon is 47.52 meters. Hence, this is the required solution.

4 0

3 years ago