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stiks02 [169]
3 years ago
5

Compare and contrast the two different types of mechanical waves?

Physics
1 answer:
prohojiy [21]3 years ago
5 0
There are longitudinal and transverse.  Both types of mechanical waves require a medium, transport energy, and have defined wavelengths, frequencies, and speeds.
Differences are that transverse waves oscillate along a direction perpendicular to the direction of travel (like shaking a rope up and down).  Longitudinal waves like oscillations along a spring and sound waves, oscillate back and forth along the direction of travel. 
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A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg
lidiya [134]

Answer:

7.5 kg

Explanation:

We are given that

m_1=10 kg

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

m_2=20 kg

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

20\times 1=10\times (1.5-1)+m\times (1.5+0.5)

20=10(0.5)+2m

20=5+2m

2m=20-5=15

\implies m=\frac{15}{2}

m=7.5 kg

Hence, mass 7.5 kg   must be on the other end if the plank remains balanced.

3 0
3 years ago
Read 2 more answers
Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un
Naya [18.7K]

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

Equating both we get :

C_{liquid}=1.258 \ J/g^0C.

7 0
3 years ago
Which of the following statements about transition metals is true?
Levart [38]
It would probably be C
7 0
4 years ago
Read 2 more answers
A ski jumper starts with a horizontal take-off velocity of 25 m/s and lands on a straight landing hill inclined at 30o. Determin
melamori03 [73]

Answer:

0.34s, 8.5m,31.89m

Explanation:

The above motion defines a projectile motion.

Now the athletes lands on a cliff 30° to the horizontal this means the velocity at that point would be 25m/s cos30°

Now from Newton's law of motion.

The body would be decelerating so,

V = u - gt

Where u is initial velocity and v is final velocity. g is acceleration of free fall due to gravity.

Hence,

V-U/ -g = t

Hence 25cos30 - 25/ -9.8 = 0.34s.

2.Now the length of the jump is defined as the total horizontal distance which is marked off by the horizontal velocity and time taken for take off and landing.

Hence Distance,S = u × t

25 ×0.34 =8.5m.

3. The maximum height is defined that at that point the Final velocity is 0m/s

Now the initial velocity is 25m/s

From Newton's law that;

V2= U2 -2gH; where U and V are initial and final velocity and H is height.

Hence H = V2-U2/-2g

=(0)^2- (25)^2/ -2×9.8

= -625/-19.6 =31.89m

8 0
3 years ago
How does eating food produced locally benefit the environment?
fomenos

Answer:

Eating food produce locally makes it where big trucks don't have to bring it to the restaurant  

Explanation:

When the big trucks drive it they release pollutants into the air so therefore when you get stuff produced locally you don't have the big trucks polluting the air. So therefore it is better for the environment.

6 0
3 years ago
Read 2 more answers
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