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lord [1]
3 years ago
7

Bis(bipyridyl)cadmium(II) chloride write the chemical formula

Chemistry
2 answers:
baherus [9]3 years ago
7 0

<u>Answer:</u> The chemical formula for this complex is [Cd(C_{10}H_8N_2)_2]Cl_2 or [Cd(bipy)_2]Cl_2

<u>Explanation:</u>

2,2'-Bypridine is a bidentate chelating ligand which forms complex with many transition metals. Its chemical formula is C_{10}H_8N_2

Bidentate ligands are the ligands which donate two pairs of electrons to the metal atom.

This complex contains two spheres: Primary sphere and secondary sphere

Primary sphere is the sphere which satisfies the primary valency of the metal and the coordination sphere satisfies the secondary valency of the metal known as secondary sphere.

Chlorine is satisfying the primary valency of the metal and bipyridyl is satisfying the secondary valency of the metal.

The chemical formula for this complex is [Cd(C_{10}H_8N_2)_2]Cl_2 or [Cd(bipy)_2]Cl_2 and its structure is given in the image attached.

GREYUIT [131]3 years ago
3 0
Following are the chemical and structural formulae of said complex compound, 

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What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?
Andreyy89

Answer:

49.35  mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

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At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is \frac{56.2}{820}

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3 0
2 years ago
When sulfur burns, it forms sulfur dioxide (SO2). Its chemical reaction is S + O2 → SO2.
Elenna [48]

Answer:

The mass of SO2 will be equal to the sum of the mass of S and O2.

Explanation:

This can be explained by the <em>Law of Conservation of Mass</em>. This law states that mass can neither be created nor destroyed. Knowing this, we can say that the reactants of a chemical reaction must be equal to the products.

In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.

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