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Nostrana [21]
3 years ago
10

Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.

Chemistry
1 answer:
Drupady [299]3 years ago
3 0

Answer:

Honestly have no clue

Explanation:

................

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Assuming that both cases describe hydrogen‑like atoms with one electron, for which case is more energy emitted or absorbed?
Nana76 [90]

Assuming that both cases describe hydrogen‑like atoms with one electron, More energy is emitted or absorbed for case 2. The correct option is D.

<h3>What is emitting of energy, by electron?</h3>

The energy of the electron decreases as it changes levels, and emission of photons happens in the atom.

With the electron moving from a higher to a lower energy level, the photon is emitted. The photon's energy is the same as the energy lost by an electron moving to a lower energy level.

Thus, the correct option is D, More energy is emitted or absorbed for case 2.

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5 0
2 years ago
Write an overall equation for the acid-base reaction that would be required to produce the following salt. MgCl2
harina [27]
Mg+Cl2--> MgCl2

Magnesium plus chlorine equals magnesium chloride
7 0
3 years ago
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How is the filter bed cleaned
siniylev [52]

Answer:

The filter bed is cleaned by occasional backwashing ;-; im sorry if this isn't a great answer but I tried

5 0
3 years ago
2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

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5 0
1 year ago
Match the following items.
navik [9.2K]

Answer:

1. not affected by a magnet                      1 liquid

2. mostly space                                          2 solid

3. flows freely but particles still attract 3 proton

4. positively charged particles                  4 gas

5. free to move in all space                       5 alpha particles

6. negatively charged particles                 6 atoms

7. atoms nearly fixed in space                   7 gamma ray                                                    8. helium nucleus                                        8 electron (beta)

6 0
2 years ago
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