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Elodia [21]
3 years ago
10

Does sound travel much faster than light ?

Physics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

nothing travels faster than light

Example:

You’ll always see lightning before you hear it, because typically lightning will be a mile away, two miles away.

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Two large, flat, horizontally oriented plates are parallel to each other, a distance d apart. Half-way between the two plates th
fgiga [73]

Answer:

Explanation:

Let the potential difference between the plate is V . Then in the first case

Electric field E between plate

E₁ = V / d

where d is separation between plate

When the plate separation becomes d / 2

Electric field E between plate

E₂ = V / d /2

= 2 V / d =2E₁

Or twice the earlier field

5 0
3 years ago
A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take
defon
Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t 

We calculate as follows:

500 W = 15000 J / t
t = 30 s</span>
3 0
3 years ago
Find the wavelength of a 26 Hz sound wave traveling through air at 20ºC. Hint: speed of sound at 20ºC = 343 m/s
Usimov [2.4K]
The correct answer for the question that is being presented above is this one: "B. 13m." 

The formula of wave velocity is this:
wave velocity = f * <span>λ
</span>λ = v / f
<span>λ</span> = 343m/s / 26Hz
λ = 13.20m .. ans (b) 

Here are the following choices:
A. 5m 
B. 13m 
C. 28m 
D. 58m 
3 0
3 years ago
A dragster travels 1/4 mi in 6.7 s. Assuming that acceleration is constant and the dragster is initially at rest, what is its ve
nlexa [21]
V0=0m/s (initially at rest)
t=6,7s
s=1/4mi=402,336m
s=(a*t^2)/2   ->   a=2*s/t^2    ->  a=2*402,336m/(6,7s)^2
a=804,672/44,89=17,93 m/s^2
<span>v=v0+at
</span>v=0+17,93 m/s^2 * 6,7s = 120,131 m/s = 432,4716 km/h
3 0
3 years ago
Read 2 more answers
Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objec
balandron [24]

By definition, the gravitational force is given by:

F = G(\frac{m1m2}{r^2})

Where,

G: gravitational constant

m1: mass of object 1

m2: mass of object 2

r: distance between objects:

We know that the force is equal to 10N:

G(\frac{m1m2}{r^2}) = 10

If the distance is double we have:

F = G(\frac{m1m2}{(2r)^2}) = G(\frac{m1m2}{4r^2}) = \frac{1}{4}G(\frac{m1m2}{r^2})

\frac{1}{4}(10) = 2.5

Therefore, the new force is:

2.5 newtons

Answer:

the changed force of attraction between them is:

A. 2.5 newtons

7 0
3 years ago
Read 2 more answers
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