<span>Hibernation. Hibernation is a state of animal dormancy characterized by inactivity, slow breathing, and a lowered metabolic rate in response to lower temperatures (specifically during winter). During the rainy season finding the right food for many animals can be very challenging-- that's why they often have to enter a phase of inactivity which helps them save energy and survive the winter without eating much. Animals like the Polar bear store energy by eating extra food and storing it as body fat which they then use later on as energy while sleeping or during pregnancy. This period of inactivity is typical with endotherms which regulate heat by its internal bodily functions instead of relying on ambient heat. The animal decreases its metabolic rate, which then decreases body temperature and this may last several days, weeks, or months depending on the species, ambient temperature, time of year, and individual's body condition.</span>
Using Coulomb's Law <span>
F = {k(Q1)(Q2)}/r²
Where F =force in Newtons, k = Coulomb constant, Q1 = - Q2=
charge of the objects in Coulumbs, and r is the distance between the objects.
Solving for r:
r = sqrt[{k(Q1)(Q2)}/F]
where k = 8.897 x 10^9 N•m²/C², Q1 = 2.5 C, Q2 = -2.5 C, and
F = -700 N
Note: Negative magnitude of Force indicates attraction.
<span>r = 8,912.77 m</span></span>
S- sexually T- transmitted D- disease
These are usually transmitted by some sort of sexual inter-coarse .
some examples of STD's are HIV,chlamydia,genital herpes,&gonorrhea . These are not the only ones there are many other types of STDs
Answer:
Mg= 1.3418 kg*m/s
Explanation:
Mass of rifle
Recoil velocity of rifle
Momentum of rifle
mass of bullet
mb=7.2x10^{-3} kg=0.0072 kg
velocity of bullet relative to muzzel
v_{b} = 601 m/s
velocity of bullet relative to earth= 601 - 1.95=599.05 m/s
momentum of bullet
the momentum of the propellant gases = momentum of rifle - momentum of bullet
the momentum of the propellant gases
Mg=5.655 -4.3132
Mg= 1.3418 kg*m/s
the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle is 1.3418 kgm/s
Answer:
t = 0.657 s
Explanation:
First, let's use the appropiate equations to solve this:
V = √T/u
This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.
Where:
V: Speed of the disturbance
T: Tension of the rope
u: linear density of the rope.
The density of the rope can be calculated using the following expression:
u = M/L
Where:
M: mass of the rope
L: Length of the rope.
We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:
u = 2.31 / 10.4 = 0.222 kg/m
Now, replacing in the first equation:
V = √55.7/0.222 = √250.9
V = 15.84 m/s
Finally the time can be calculated with the following expression:
V = L/t ----> t = L/V
Replacing:
t = 10.4 / 15.84
t = 0.657 s
