Answer:
0.27 m/s and 0.01 m/s
Explanation:
Given that
Mass of the bullet, m = 3 g = 0.003 kg
Velocity of the bullet, v = 230 m/s
Weight of the rifle, w = 25 N
From this, we know that the mass of the rifle, M = 25/9.8 = 2.55 kg
Using the law of conservation of momentum, we know that
Momentum of the gun = momentum of the bullet
M.g * V.g = m.b * v.b
2.55 * V.g = 0.003 * 230
2.55V.g = 0.69
V.g = 0.69 / 2.55
V.g = 0.27 m/s
If weight of the shooter = 650, then his mass = 650/9.8 = 66.33 kg
The recoil speed of the shooter is
0.69 / 66.33 = 0.010 m/s