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3 years ago

A 75.0-kg person climbs stairs, gaining 2.50 m in height. Find the work done to accomplish this task.

Physics

1 answer:

ololo11 [35]3 years ago

4 0

Answer:

$W=1837.5J$

Explanation:

A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:

$W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d$

In this case, we have:

$F=mg\\h=dcos\theta$

So, replacing this:

$W=mgh\\W=75kg*9.8\frac{m}{s^2}*2.5m\\W=1837.5J$

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A positively charged rod is brought close to one end of an uncharged metal rod but does not actually touch it. What type of char

svlad2 [7]

Answer:

The end of the neutral rod which is the closest part to the charged rod would acquire a negative charge.

Explanation:

One of the rods is positively charged and one of them is neutral.

And the important part is that <u>they do not touch one another</u>, but get close to each other.

In this case, the end of the neutral rod which is the closest part to the charged rod would acquire a negative charge. This is because of the Coulomb's Law. The opposite charges exert an attractive force to each other. The positive charges attract the negative charges on the neutral rod.

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3 years ago

A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an

professor190 [17]

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, $A_1=0.01\ m^2$

Area, $A_2=0.04\ m^2$

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}$

$F_2=\dfrac{F_1}{A_1}\times A_2$

$F_2=\dfrac{8800}{0.01}\times 0.04$

$F_2=35200\ N$

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

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3 years ago

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Answer:

V=9.60m/s

Attached is the solution

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3 years ago

The light reactions could be viewed as analogous to a hydro-electric dam. In that case, the wall of the dam that holds back the

Viktor [21]

The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.

Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.

In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.

In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.

If you need to learn more about light reactions click here:

brainly.com/question/26623807

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1 year ago