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kvv77 [185]
3 years ago
13

Moving from 0m/s to 25m/s in 8.0s equals an average acceleration of...

Physics
2 answers:
Verdich [7]3 years ago
5 0

Moving from 0m/s to 25m/s in 8.0s equals an average acceleration of 3.125 m/s^2. You get this through the following steps:

25-0/8-0 = 3.125 m/s^2

since the average acceleration (a) = change in vvelocity over change in time


Answer: 3.125 m/s^2


Shoutout to: @Mr. Toto




sad!; live


arlik [135]3 years ago
4 0
<h2>Answer:</h2>

Average acceleration = 3.124 m/s²

<h3>Explanation:</h3>

Given data:

Initial velocity = 0 m/s

Final velocity = 25 m/s

Time = 8.00 s

Average acceleration = ?

Solution:

Average acceleration = (Final velocity - Initial velocity)/time

By putting values in above formula:

Average acceleration = (25 - 0)/8

                                  = 25/8

                                  = 3.125 m/s²

Hence an object moving from 0m/s to 25m/s of velocity in 8.0s has an average acceleration of 3.125 meter per second square. Acceleration is the rate of change of velocity. And average acceleration is equal to change in final velocity and initial velocity divided by time.


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What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

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5 0
3 years ago
A uniform thin wire is bent into a quarter-circle of radius a = 20.0 cm, and placed in the first quadrant. Determine the coordin
Mashcka [7]

Answer:

r_{cm}=[12.73,12.73]cm

Explanation:

The general equation to calculate the center of mass is:

r_{cm}=1/M*\int\limits {r} \, dm

Any differential of mass can be calculated as:

dm = \lambda*a*d\theta  Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}

So, the differential of mass is:

dm = \frac{2M}{a\pi}*a*d\theta

dm = \frac{2M}{\pi}*d\theta

Now we proceed to calculate X and Y coordinates of the center of mass separately:

X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta

Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta

Solving both integrals, we get:

X_{cm}=2*a/\pi=12.73cm

Y_{cm}=2*a/\pi=12.73cm

Therefore, the position of the center of mass is:

r_{cm}=[12.73,12.73]cm

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2 years ago
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3 years ago
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Answer:

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8 0
2 years ago
Read 2 more answers
[Assume g = 10m/s?] If a girl is running along a straight road with a uniform velocity 1.5 m/s, find her acceleration. (Ans: 0)
DerKrebs [107]

Answer:

Her acceleration is 0 m/s²

Explanation:

We note that the motion of the girl is on a straight road, therefore;

The vertical acceleration (e.g. due to gravity, <em>g)</em> on the horizontal motion = 0

The horizontal acceleration, a = (Change in velocity, Δv)/(Change in time, Δt)

For uniform velocity, the change in velocity, Δv = 0

Therefore, fore any change in time, Δt, we have;

a = Δv/Δt

Her acceleration, a = 0/Δt = 0

Her acceleration, a = 0 m/s²

7 0
2 years ago
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