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3 years ago

If your customers are satisfied 11 out of 15 times how many are satisfied If 350 people come in on Black Friday

2 answers:

6 0

If 350 divided by 15 is 23.3333333 then we can round that to 23. 11 multiples by 23 is 253. So the answer is about 253 satisfied customers.

Margaret [11]3 years ago

6 0

Answer:

257 people are satisfied

Step-by-step explanation:

11/15 is the fraction that are satisfied

11/15 * 350 =256.6(repeating)

Rounding to the nearest whole person

257 people are satisfied

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A principal of $1800 is invested at 4% intrest, compounded annually. How much will the investment be worth after 8 years?

zavuch27 [327]

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4 years ago

Sally will measure the length of a wall in both centimeters and meters. Will there be fewer centimeters or fewer meters? Explain

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4 years ago

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Please someone help me and do not just write anything explain thank you . use the information provided to write the vertex form

notka56 [123]

Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c

the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating

y=-2x^2-12x-28
a=-2
b=-12

xvalue of vertex is -(-12)/(2*-2)=12/-4=-3

x value of vertex is -3

plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10

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vertex is (-3,-10)

5 0

3 years ago

The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.

NISA [10]

Answer:

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8.2$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.2$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$