3 years ago

Can I have help and pls don't answer if you don't know

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

7 0

Answer:

I think its A

Step-by-step explanation:

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Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y

netineya [11]

The diagonals of a parallelogram are congruent

The length WY is 32

<h3>How to determine the length WY</h3>

Given that:

$WA = x^2 - 48$ and

$AY = x^2 - 6x$

Then, we have:

$x^2 - 48 = x^2 - 6x$ diagonal

Subtract x^2 from both sides

$- 48 =- 6x$

Divide both sides by -6

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The length WY is calculated as:

$WY=2 * WA$

So, we have:

$WY=2 * [x^2 - 48]$

Substitute 8 for x

$WY=2 * [8^2 - 48]$

Simplify

$WY=32$

Hence, the length WY is 32

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brainly.com/question/10062747

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