Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
Answer:
1.042g/cm^3
Step-by-step explanation:
Answer:
3x^2 -4
Step-by-step explanation:
F(x)=2x^2+3 and g(x)=x^2-7
(f+g)(x) =
We add the two functions together
(f+g)(x) =2x^2+3+x^2-7
I like to line them up vertically
(f+g)(x) =
2x^2 +3
+x^2 -7
------------------
3x^2 -4
