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galben [10]
3 years ago
9

PLEASE HELP!!!!

Physics
2 answers:
Alecsey [184]3 years ago
5 0
Use the equation, F= m(mass)x a (acceleration) to find the net force.
vovikov84 [41]3 years ago
3 0

Answer:

a. 2000 N

b. acceleration of the motorcycle would decrease

Explanation:

a. acceleration = (final speed - initial speed)/time

a = (30 - 0)/3 = 10 m/(s^2)

Force = mass * acceleration

F = 200 * 10 = 2000 N

b. If the the coefficient of friction between the tire and the pavement increased greatly, part of the force generated by the engine would go to overcome this friction, then the force that goes into acceleration of the motorcycle would be less than case a, as a consequence, its acceleration would decrease (mass remains the same).

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Part A
7nadin3 [17]

Answer:

2.5 m/s²

Explanation:

Using the formula, v = u + at ( v = Final velocity; u = Initial velocity; t = Time; a = Acceleration)

25 = 0 + 10a

a = 25/10 = 2.5 m/s²

8 0
3 years ago
A 23.8 kg space rock is pushed with a force and accelerates at 8.97 m/s/s. How much force was applied?
kotegsom [21]

m=23.8kg a=8.97m/s^2 Fnet=? Fnet=ma=(23.8kg)(8.97m/s^2)=213.486N

5 0
3 years ago
Which has more momentum, a heavy truck moving at 30 miles per hour or a light truck moving at 30 miles per hour?
valentina_108 [34]
A heavy truck moving a 30 mph. It has more mass.
7 0
3 years ago
Read 2 more answers
Which description correctly summarizes how an electric motor causes an axle to turn?
alexira [117]

Answer:

B on edge

Explanation:

the piles of the magnetic field generated around the armature are attracted to the opposite poles of the permanent magnent. As the opposite poles align, the commutator reverses the current direction so like poles are aligned and the armature continues to spin

6 0
3 years ago
A child approaches a stop sign and applies the brakes to slow to a stop. If the bicycle and child were originally traveling at 9
user100 [1]

Answer:

7.5secs

Explanation:

Using the equation of motion

v = u + at

v is the final velocity = 0m/s

u is the initial velocity = 9m/s

a is the deceleration = -1.2m/s²

t is the required time

Substitute;

0 = 9 + 1.2(t)

-9 = -1.2t

t = -9/-1.2

t = 7.5secs

hence it takes the child 7.5secs to stop

6 0
3 years ago
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