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galben [10]
4 years ago
9

PLEASE HELP!!!!

Physics
2 answers:
Alecsey [184]4 years ago
5 0
Use the equation, F= m(mass)x a (acceleration) to find the net force.
vovikov84 [41]4 years ago
3 0

Answer:

a. 2000 N

b. acceleration of the motorcycle would decrease

Explanation:

a. acceleration = (final speed - initial speed)/time

a = (30 - 0)/3 = 10 m/(s^2)

Force = mass * acceleration

F = 200 * 10 = 2000 N

b. If the the coefficient of friction between the tire and the pavement increased greatly, part of the force generated by the engine would go to overcome this friction, then the force that goes into acceleration of the motorcycle would be less than case a, as a consequence, its acceleration would decrease (mass remains the same).

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Match these items. 1 . full moon a visible half-circle 2 . first-quarter moon darkest phase of the moon 3 . 13 degrees when the
konstantin123 [22]

Answer:

1. First-quarter moon.

2. New moon.

3. Full moon.

4. 13 degrees.

5. 29 1/2 days.

Explanation:

A moon can be defined as the natural satellite of planet earth that shines as a result of the sun's reflected light, as it revolves around the earth from west to east in 29½ days.

1. First-quarter moon: a visible half-circle.

2. New moon: darkest phase of the moon.

3. Full moon: when the the Earth is between the sun and the moon.

4. 13 degrees: this is a measurement of how far the moon advances each day in orbit.

5. 29 1/2 days: the time the Earth must rotate to return to same position relative to the moon.

6 0
3 years ago
A 64.9 kg sprinter starts a race with an acceleration of 3.89 m/s2. She keeps this acceleration for 17 m and then maintains the
xxMikexx [17]

Answer:

Time of race  = 10.18 s

Explanation:

She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash

Time to travel 17 m can be calculated

         s = ut + 0.5at²

         17 = 0 x t + 0.5 x 3.89 x t²

          t = 2.96 s

Velocity after 2.96 seconds

          v = 3.89 x 2.96 = 11.50 m/s

Remaining distance = 100 - 17 = 83 m

Time required to cover 83 m with a speed of 11.50 m/s

          t=\frac{83}{11.50}=7.22s

Time of race = 2.96 + 7.22 = 10.18 s

3 0
3 years ago
In Pensacola in June, high tide was at noon. The water level at high tide was 12 feet and 2 feet at low tide. Assuming the next
Sveta_85 [38]
<span>To answer this question, the equation that we will be using is:
 y = A cos bx + c
 where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
  x = t and y = f(t)

  A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
  b = 2 pi / 12 = pi/6
  c = 1/2 (Xmax + Xmin)
  12+2/2 = 7
  answer: f(t) = 5 cos pi/6 t + 7 </span>
8 0
4 years ago
Can the velocity of a body revese the direction when acceleration is constant?
andriy [413]

Answer:

Yes, the velocity of the object can reverse direction when its acceleration is constant. For example consider that the velocity of any object at any time t is given as: ... At At t = 0 sec, the magnitude of velocity is 2m/s and is moving in the forward direction i.e.v (t) = -2.

7 0
3 years ago
What’s the difference between applied and pure research
Ket [755]

Answer:

Pure research is conducted without any specific goal in mind. Applied research is conducted in order to solve a specific and practical problem, unlike pure research. Hope this helped.

8 0
3 years ago
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