The wave diagramed in blue.
The temperature rises until the water reaches the next change of state — boiling. As the particles move faster and faster, they begin to break the attractive forces between each otherand move freely as steam — a gas. The process by which a substance moves from the liquid state to the gaseousstate is called boiling.
Answer:
Yes, if the two carts are moving into opposite directions
Explanation:
The total momentum of the system of two carts is given by:

where
m1, m2 are the masses of the two carts
v1, v2 are the velocities of the two carts
Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.
We want to know if it is possible that the total momentum of the system can be zero, so it must be:

From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.
Answer:
The answer to the question is;
Based on their acceleration the rank of the satellites from largest to smallest is.
B >→ A >→ E >→ C >→ F >→ D.
Explanation:
Acceleration is given by 
Therefore the acceleration for each of the satellite is given by
Satellite A)
= 5.12 m/s²
Satellite B)
= 10.24 m/s²
Satellite C)
= 2.56 m/s²
Satellite D)
= 0.16 m/s²
Satellite E)
= 2.88 m/s²
Satellite F)
= 0.64 m/s²
Therefore in order of decreasing acceleration, from largest to smallest we have
Satellite B) > Satellite A) >Satellite E) >Satellite C)>Satellite F)>Satellite D).
Answer:
14.8 kg
Explanation:
We are given that




We have to find the mass of the pulley.
According to question



Moment of inertia of pulley=

Where 



Hence, the mass of the pulley=14.8 kg