Question

How many seconds will elapse between seeing lightning and hearing the thunder if the lightning strikes 4.5 mi (23,760 ft) away and the air temperature is 74.0°F?

Answer 1

Answer:

t = 20.96 seconds

Explanation:

given,

lightning strikes at = 4.5 mi( 23,760 ft)

air temperature =74.0°F

74.0°F = 23.3 °C

speed of the sound at 23.3 °C

V = 331.5 + 0.6 × T

V = 331.5 + 0.6 × 23.3

   = 345.48 m/s

distance given = 4.5 mile

1 mile = 1609.4                

4.5 mile = 4.5 × 1609.4 = 7242.3 m            

time taken =

$t =\dfrac{d}{v}$

$t =\dfrac{7242.3}{345.48}$

t = 20.96 seconds

hence, time taken by the sound to reach by the observer is 20.96 sec.