1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
romanna [79]
3 years ago
7

How many seconds will elapse between seeing lightning and hearing the thunder if the lightning strikes 4.5 mi (23,760 ft) away a

nd the air temperature is 74.0°F?
Physics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

t = 20.96 seconds

Explanation:

given,

lightning strikes at = 4.5 mi( 23,760 ft)

air temperature =74.0°F

74.0°F = 23.3 °C

speed of the sound at 23.3 °C

V = 331.5 + 0.6 × T

V = 331.5 + 0.6 × 23.3

   = 345.48 m/s

distance given = 4.5 mile

1 mile = 1609.4                

4.5 mile = 4.5 × 1609.4 = 7242.3 m            

time taken =

t =\dfrac{d}{v}

t =\dfrac{7242.3}{345.48}

t = 20.96 seconds

hence, time taken by the sound to reach by the observer is 20.96 sec.

You might be interested in
Light of wavelength 608.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 88.5 cm from the slit.
Effectus [21]

Answer:

The width of the slit is 0.167 mm

Explanation:

Wavelength of light, \lambda=608\ nm=608\times 10^{-9}\ m

Distance from screen to slit, D = 88.5 cm = 0.885 m

The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m

We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :

y=\dfrac{mD\lambda}{a}

where

a = width of the slit

a=\dfrac{mD\lambda}{y}

a=\dfrac{5\times 0.885\ m\times 608\times 10^{-9}\ m}{0.0161\ m}

a = 0.000167 m

a=1.67\times 10^{-4}\ m

a = 0.167 mm

So, the width of the slit is 0.167 mm. Hence, this is the required solution.

7 0
3 years ago
Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0
3 years ago
PLEASEE HELP !! <br><br> explain how a leaf is organic matter
avanturin [10]
A leaf is organic matter because organic matter refers to anything from something living. because a leaf is living or was at one point it is organic matter
6 0
3 years ago
Two masses are attracted by a gravitational force of 7 N.
damaskus [11]

Answer:

The answer to your question is: F  = 0.4375 N. The force will be 16 times lower than with the first conditions.

Explanation:

Data

F = 7 N

F = ?  if the masses is quartered

Formula

F = \frac{Km1m2}{r2}

Process

Normal conditions F = Km₁m₂/r²  = 7              

When masses quartered        F = K(m₁/4)(m₂/4)/r²  = ?

                                                F = K(m₁m₂/16)/r²

                                                F = K(m₁m₂/16r²      = 7/16  = 0.4375 N

3 0
3 years ago
Can anyone help me with this question please​
JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

  1. v=u+at = 6=2+a*2

6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

=4+20

v=24m/sec

5.v=u+at

=5+8*10

=5+80

V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

these are your missing values

5 0
3 years ago
Other questions:
  • SpongeBob noticed that his favorite pants were not as clean as they used to be. His friend Sandy told him that he should try usi
    15·1 answer
  • What is the angle between the electric field and the axis of the filter?
    15·1 answer
  • A girl is bouncing on a trampoline where is her gravitational potential energy a maximum and where is her kinetic energy maximum
    10·1 answer
  • What is the mass of an object that requires 100N of force in order to accelerate it at 10m/s2 ?
    8·2 answers
  • A 7.1 cm diameter horizontal pipe gradually narrows to 5.4 cm . When water flows through this pipe at a certain rate, the gauge
    6·1 answer
  • When a unbalanced force act on an object , the object moves with what motion?
    6·1 answer
  • Ann and Beth are measuring mass of an object, Ann reports a mass of 6 g while Beth obtains 6.0 g what are the range of uncertain
    11·1 answer
  • A curve ball is a type of pitch in which the baseball spins on its axis as it heads for home plate. If a curve ball is thrown at
    6·1 answer
  • This equation goes with which law?
    10·1 answer
  • Can someone please help me on thisss
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!