Question

What is the solution to the equation below? square root of 4-3x divided by square root of 3x equals 2

Answer 1

Answer:

B.$x=\frac{4}{15}$

Step-by-step explanation:

• $\frac{\sqrt{4-3x}}{\sqrt{3x} } =2$can be simplify by doing some algebra.
• Particulary, in this case, $\frac{\sqrt{4-3x}}{\sqrt{3x} } =\sqrt{\frac{4-3x}{3x} }$, because of the distributive property with respect to division and multiplication.
• Then, by dividing numerator and denominator by 3x inside the power we get $\sqrt{\frac{\frac{4}{3x}-1}{1}}=\sqrt{\frac{4}{3x}-1} =2$.
• To dispose of the squared root, we raise to power 2 both sides of the equation, to obtain the following expression: $\frac{4}{3x}-1=4$.
• Finally, we just have to clear out the value of x from this expression, by addding 1 both sides of the equation: $\frac{4}{3x}=5$, and then by multiplying both sides by 3x, and then dividing the result by 15. This yields $x=\frac{4}{15}$