Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².
Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.
Given,
Radius of flywheel (r) = 1.96 cm = 0.0196m
Angular acceleration (α)= 13.0 rad/s²
The tangential acceleration formula is at=rα
where, α is the angular acceleration, and r is the radius of the circle.
using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².
The tangential acceleration is 0.2548 m/s².
Learn more about the Tangential acceleration with the help of the following link:
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Answer: The first two weeks after conception are known as the germinal stage.
Explanation:
Answer: Physical Quantity
Explanation: A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit.
Answer:
Total pressure= 120945[Pa]
Force exerted = 29026800 [N] or 29.02*10^6 [N]
Explanation:
We know that the total pressure is the result of the sum of the atmospheric pressure plus the manometric pressure. The equation is:

In this problem we know the atmospheric pressure 101.325x10^3 [Pa], therefore we need to find the manometric pressure.
The manometric pressure in the bottom of the swimming pool depends only on the water column of water generated (depth of the swimming pool)

where:
density = density of the water 1000 [kg/m^3]
g= gravity [m/s^2]
h= column of water (meters)
replacing the values:
![Pman= 1000 *9.81* 2 = 19620 [Pa]\\\\](https://tex.z-dn.net/?f=Pman%3D%201000%20%2A9.81%2A%202%20%3D%2019620%20%5BPa%5D%5C%5C%5C%5C)
The total pressure will be:
![Ptotal= 101325+19620 = 120945 [Pa]\\\\](https://tex.z-dn.net/?f=Ptotal%3D%20101325%2B19620%20%3D%20120945%20%5BPa%5D%5C%5C%5C%5C)
The force exerte on the bottom is defined by the following expression:
