A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.
2 answers:
<u>Answer:</u>
The bullet would travel 130 m in 1.3 sec
<u>Solution: </u>
The bullet leaves a gun with a horizontal velocity of 100 m/s
We know that the velocity means the distance travelled per sec
The formula for the distance with respect to speed and time is
Let us assume the bullet travelled distance S and the time is 1.3 sec
So,
Hence, the bullet travel 130 m in 1.3 sec
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Answer:
38.3 m/s
Explanation:
To find vertical component of initial velocity, you'd have to use sine ratio:
is vertical component of initial velocity and
is initial velocity given which is 50 m/s.
A stone is projected at an angle of 50 degrees so = 50°. Substitute in the formula:
Therefore, the vertical component of initial velocity is approximately 38.3 m/s
(The picture is also attached for visual reference!)
Answer:
Explanation:
Given that,
The compression in the spring, x = 0.0647 m
Speed of the object, v = 2.08 m/s
To find,
Angular frequency of the object.
Solution,
We know that the elation between the amplitude and the angular frequency in SHM is given by :
A is the amplitude
In case of spring the compression in the spring is equal to its amplitude
So, the angular frequency of the spring is 32.14 rad/s.