Answer:
0.41s
8.01m/s
Explanation:
Using the formula; v = u + at
Where;
u = initial velocity (m/s)
v = final velocity (m/s)
t = time (s)
a = acceleration (m/s²)
According to the provided information, u = 4m/s, s = 8m,
V = u + at
4 = 0 + 9.8t
4 = 9.8t
t = 0.41s
b) v = u + at
v = 4 + 9.8(0.41)
v = 4 + 4.018
v = 8.018m/s
With that information you can only suppose a uniformly accelerated motion. This is, acceleration is constant.
Then, acceleration = change in velocity / change in time = (58 -54)km/h / 2 h = 4km/h / 2 h = 2 km/h^2
Then the equation for velocity, V is
V = Vo + a*t = Vo + 2 (km/h^2) * t = Vo + 2t
Vo is the initial velocity, which you can find using V = 54km/h and t = -2
Vo = V after 2 hours - a*(2hours) = 54km/h - 2(km/h^2)*2h = 54km/k - 4km/h = 50km/h
Then, the equation is: V = 50 km/h + 2t
Valid for constant acceleration.
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