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PSYCHO15rus [73]
3 years ago
8

A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.

Physics
2 answers:
salantis [7]3 years ago
5 0

Answer:

130m

Explanation:

You just have to multiply velocity by the time traveled:

100m/s * 1.3s = 130m!

juin [17]3 years ago
3 0

<u>Answer:</u>

The bullet would travel 130 m in 1.3 sec

<u>Solution: </u>

The bullet leaves a gun with a horizontal velocity of 100 m/s

We know that the velocity means the distance travelled per sec

The formula for the distance with respect to speed and time is

Distance = velocity \times time

Let us assume the bullet travelled distance S and the time is 1.3 sec

So, S = (100 \times1.3) m = 130 m

Hence, the bullet travel 130 m in 1.3 sec

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An aluminium object has a mass of 27kg and density of 2700 the object is atached to a spring and immerged in a tank of water det
laiz [17]

Answer:

0.01m^3

Explanation:

m=27

density=2700

density=mass/volume

2700=27/volume

volume=27/2700=0.01

8 0
2 years ago
The friends take a few minutes to discuss their ideas. Which of Amy's comments with respect to a charged particle moving in a ma
Marizza181 [45]

Answer:

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false.

Explanation:

The equation for the magnetic force on a charge q moving at velocity v on a magnetic field B is given by the (vectorial) Lorentz Force Law F=qv\times B

From it we can clearly see that the <em>magnitude of the magnetic force </em>exerted on the particle is <em>proportional to the magnitude of the charge q and to the speed v of the particle</em>, and that it is also <em>perpendicular to the particle's velocity</em>. This means that at each instant it moves perpendicularly to the force, so <em>the work done by the magnetic force on the particle is zero</em>.

The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false not only for this but for any force, a force always perpendicular to a velocity will curve the trajectory.

7 0
3 years ago
Which three characteristics make iron a good blackbody radiator?
victus00 [196]

Answer:

A, C, and D

Explanation:

Just did the quiz

4 0
3 years ago
WHO WANts TO HAVE SOME GLIZZY ACTION
Lilit [14]
Bruh huh.............
6 0
2 years ago
While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. how much time does it ta
Yuri [45]

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).

When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.

Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.

The equation of motion is stated as,

v = u + at

v² = u² + 2as

A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

1.5t = 6

t = 4 seconds

Hence, the time taken is 4 s.

The complete question is:

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

To know more about acceleration refer to:  brainly.com/question/12550364

#SPJ4

8 0
1 year ago
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