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Ymorist [56]
3 years ago
11

Give an example in which velocity is zero yet acceleration is not.

Physics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

Explanation:

The time rate of change of displacement is called velocity and it is a vector quantity.

The time rate of change of velocity is called acceleration, it is also a vector quantity.

A body can have zero velocity and non zero acceleration.

For example, when you throw a ball vertically upwards with some velocity, the ball reaches to maximum height. At maximum height its velocity is zero but an acceleration is acting on the ball which is the acceleration due to gravity and which acts vertically downwards always.

NeTakaya3 years ago
4 0

Answer:

(1) Oscillation of simple pendulum (2) Dropping a ball from a certain height vertically

Explanation:

Instantaneous velocity can be zero even if acceleration is non zero .

Example 1 : Consider the case of a simple pendulum which is oscillating, when bob is at the extreme position, then the bob stops for a moment ( velocity is zero there ) but acceleration is non zero due to which it reverses it’s motion .

Example 2 : When someone drop the ball from a certain height then the initial velocity of the ball is zero at that point but the acceleration is not zero it is in downward direction . This downward acceleration will increase the velocity from zero.

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Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
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Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
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3 years ago
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If you walk 800m north, 600m east, and 200 meters south at a speed of 1m/s. What is your velocity?
ryzh [129]

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During a compression at a constant pressure of 290 Pa, the volume of an ideal gas decreases from 0.62 m3 to 0.21 m3. The initial
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Answer:

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b) 108.38 Kelvin

Explanation:

Pressure = P = 290 Pa

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Final volume of gas = V₂ = 0.21 m³

Initial temperature of gas = T₁ = 320 K

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⇒T₂ = 320×0.21/0.62

⇒T₂ = 108.38 K

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