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Ymorist [56]
2 years ago
11

Give an example in which velocity is zero yet acceleration is not.

Physics
2 answers:
Bezzdna [24]2 years ago
7 0

Answer:

Explanation:

The time rate of change of displacement is called velocity and it is a vector quantity.

The time rate of change of velocity is called acceleration, it is also a vector quantity.

A body can have zero velocity and non zero acceleration.

For example, when you throw a ball vertically upwards with some velocity, the ball reaches to maximum height. At maximum height its velocity is zero but an acceleration is acting on the ball which is the acceleration due to gravity and which acts vertically downwards always.

NeTakaya2 years ago
4 0

Answer:

(1) Oscillation of simple pendulum (2) Dropping a ball from a certain height vertically

Explanation:

Instantaneous velocity can be zero even if acceleration is non zero .

Example 1 : Consider the case of a simple pendulum which is oscillating, when bob is at the extreme position, then the bob stops for a moment ( velocity is zero there ) but acceleration is non zero due to which it reverses it’s motion .

Example 2 : When someone drop the ball from a certain height then the initial velocity of the ball is zero at that point but the acceleration is not zero it is in downward direction . This downward acceleration will increase the velocity from zero.

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How much work is done when an engine generates 400 Watts of power in 25 seconds?
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10000 J or 10 KJ

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) A physics student wants to measure the stiffness of a spring (force required per cm stretched). He knows that according to Hoo
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3 years ago
The rectangular plates in a parallel-plate capacitor are 0.063 m x 5.4 m. A distance of 3.5 x 10^-5m separate the plates. The pl
Aleks04 [339]

The capacitance of the capacitor is 1.8\cdot 10^{-9}F

Explanation:

The capacitance of a parallel-plate capacitor is given by the equation

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the medium

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.1 is the dielectric constant

d=3.5\cdot 10^{-5}m is the separation between the plates

A=0.063m \cdot 0.054m = 0.0034 m^2 (I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)

Therefore, the capacitance of the  capacitor is

C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F

Learn more about capacitors:

brainly.com/question/10427437

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