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3 years ago

Give an example in which velocity is zero yet acceleration is not.

Physics

2 answers:

Bezzdna [24]3 years ago

7 0

Answer:

Explanation:

The time rate of change of displacement is called velocity and it is a vector quantity.

The time rate of change of velocity is called acceleration, it is also a vector quantity.

A body can have zero velocity and non zero acceleration.

For example, when you throw a ball vertically upwards with some velocity, the ball reaches to maximum height. At maximum height its velocity is zero but an acceleration is acting on the ball which is the acceleration due to gravity and which acts vertically downwards always.

NeTakaya3 years ago

4 0

Answer:

(1) Oscillation of simple pendulum (2) Dropping a ball from a certain height vertically

Explanation:

Instantaneous velocity can be zero even if acceleration is non zero .

Example 1 : Consider the case of a simple pendulum which is oscillating, when bob is at the extreme position, then the bob stops for a moment ( velocity is zero there ) but acceleration is non zero due to which it reverses it’s motion .

Example 2 : When someone drop the ball from a certain height then the initial velocity of the ball is zero at that point but the acceleration is not zero it is in downward direction . This downward acceleration will increase the velocity from zero.

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barxatty [35]

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3 years ago

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A race car starting from rest accelerates uniformly at a rate of 4.90 meters per squared. What is the cars speed after it has tr

shusha [124]

Ok, we need to find a relation for the speed as it relates to the acceleration. This is given by the integral of acceleration:

$v= \int\limits^{t}_{0} {a} \, dt' =at$

Where we have the initial velocity is 0m/s and a will be 4.90m/s².

But we see there is an issue now... We know the velocity as a function of time, but we don't know how long the car has been accelerating! We need to calculate this time by now finding the position function as a function of time. This way we can solve for the time, t, that it takes to go 200m accelerating this way and then substitute that time into our velocity equation and get the velocity.
Position is just the integral of velocity:

$s= \int\limits^{}_{} {at} \, dt = \frac{1}{2}at^2$

Where the initial velocity and initial position are both zero.

Now we set this position function equal to 200m and find the time, t, it took to get there

$\frac{1}{2}(a \frac{m}{s^2} )t^2=200m \\ \\ \frac{1}{2}4.90 \frac{m}{s^2} t^2=200m \\ \\ t^2= \frac{400m}{4.90 \frac{m}{s^2}}=81.63s^2 \\ \\ t= \sqrt{81.63s^2 } =9.04s$

Now let's put t=9.04s into our velocity equation:

$v =at=4.9\frac{m}{s^2} \times 9.04s=44.3 \frac{m}{s}$

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3 years ago

True or False? Materials that are good conductors of heat are usually poor conductors of electricity.

alexandr402 [8]

False

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5 0

3 years ago

Read 2 more answers

Afina-wow [57]

Answer:

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q................... Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V................ Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

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3 years ago

The momentum of a 0.1 kg object traveling at 2000 m/s is 20,000 kg·m/s. True or False

Alina [70]

That's false.

The definition of momentum is (mass) x (speed), so they must be multiplied.

"20,000 kg-m/s" has the correct units resulting from multiplication, but the number could only be the result of division.

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3 years ago