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3 years ago

Give an example in which velocity is zero yet acceleration is not.

Physics

2 answers:

Bezzdna [24]3 years ago

7 0

Answer:

Explanation:

The time rate of change of displacement is called velocity and it is a vector quantity.

The time rate of change of velocity is called acceleration, it is also a vector quantity.

A body can have zero velocity and non zero acceleration.

For example, when you throw a ball vertically upwards with some velocity, the ball reaches to maximum height. At maximum height its velocity is zero but an acceleration is acting on the ball which is the acceleration due to gravity and which acts vertically downwards always.

NeTakaya3 years ago

4 0

Answer:

(1) Oscillation of simple pendulum (2) Dropping a ball from a certain height vertically

Explanation:

Instantaneous velocity can be zero even if acceleration is non zero .

Example 1 : Consider the case of a simple pendulum which is oscillating, when bob is at the extreme position, then the bob stops for a moment ( velocity is zero there ) but acceleration is non zero due to which it reverses it’s motion .

Example 2 : When someone drop the ball from a certain height then the initial velocity of the ball is zero at that point but the acceleration is not zero it is in downward direction . This downward acceleration will increase the velocity from zero.

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A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the

vitfil [10]

Answer:

F₂ = -7.3 N

Explanation:

Given that,

The mass of an object, m₁ = 3.7 kg

First force, F₁ = 11 N

The net acceleration of the object is 1 m/s².

We know that,

F₁+F₂ = ma

11+F₂ = (3.7)(1)

F₂ = 3.7-11

F₂ = -7.3 N

so, the other force is 7.3 N and it is acting in west direction.

7 0

3 years ago

As an object rolls downhill, some of the energy is

Charra [1.4K]

When the object is at the top of the hill it has the most potential energy. If it is sitting still, it has no kinetic energy. As the object begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the object at the top of the hill is getting converted into kinetic energy. Hope this helped. :)

7 0

3 years ago

Read 2 more answers

Density is a property of matter that relates

tiny-mole [99]

Density is the mass of a substance per unit volume.

7 0

3 years ago

A cube has a drag coefficient of 0.8. What would be the terminal velocity of a sugar cube 1 cm on a side in air ( = 1.2 kg/mº)?

anzhelika [568]

0.495 m/s

Explanation

the formula for the terminal velocity is given by:

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ \text{where} \\ \end{gathered}$

m is the mass

g is 9.81 m/s²

ρ is density

A is area

C is the drag coefficient

then

Step 1

Let's find the mass

$\begin{gathered} \sigma=\frac{m}{v} \\ m=\sigma\cdot v \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(0.01m)^3 \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(1\cdot10^{-6}) \\ \text{mass}=2\cdot10^{-3}\operatorname{kg} \\ \text{mass}=0.002\text{ kg } \\ \text{Area}=(0.01\text{ m}\cdot0.01m)=0.0001m^2 \end{gathered}$

now, replace

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ v=\sqrt[]{\frac{2(0.002kg)(9.81\text{ }\frac{m}{s^2})}{(2\cdot10^3\frac{\operatorname{kg}}{m^3})(0.0001m^2)0.8}} \\ v=\sqrt[]{\frac{0.03924\frac{\operatorname{kg}m}{s^2}}{0.16\frac{\operatorname{kg}}{m^{}}}} \\ v=\sqrt[]{0.2452\frac{m^2}{s^2}} \\ v=0.495\text{ m/s} \end{gathered}$

hence, the answer is 0.495 m/s

3 0

1 year ago

The light bulb converts electrical energy into light and _________.

KATRIN_1 [288]

Heat is the answer but I need to use 20 characters to post :)

5 0

3 years ago