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3 years ago

When electrons are lost, a ion is formed. When electrons are gained, a ____ ion is formed.

Physics

2 answers:

xenn [34]3 years ago

6 0

Answer:

When electrons are lost, a positively charged ion is formed. When electrons are gained, a negatively charged ion is formed.

Explanation:

Atoms consist of three particles:

- Protons, positively charged, in the nucleus

- Neutrons, no charge, in the nucleus

- Electrons, negatively charged, orbiting around the nucleus

The proton and the electron have same magnitude of charge ( $e=1.6\cdot 10^{-19}C$ ), but the proton's charge is positive while the electron's charge is negative.

For a neutral atom, the number of protons is equal to the number of electrons, so the atom is electrically neutral. However, sometimes the atom can lose or gain electrons, becoming electrically charged: this is called ion. In particular:

- If the atom loses one (or more) electrons, it will remain with an excess of positive charge (because the number of protons is now greater than the number of electrons), so it will form a positively charged ion

- if the atom gains one (or more) electrons, it will remain with an excess of negative charge (because the number of protons is now smaller than the number of electrons), so it will form a negatively charged ion

choli [55]3 years ago

4 0

Answer:When electrons are lost, a positively charged ion is formed. When electrons are gained, a negatively charged ion is formed.

Explanation:

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The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el

Nana76 [90]

Answer:

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

7 0

3 years ago

A 5-turn square loop (10 cm along aside, resistance = 4.0 ) is placed in a magnetic field that makes an angle of30o with the pla

andreev551 [17]

Answer:

Explanation:

Area A of the coil = .1 x .1 = .01 m²

no of turns n = 5

magnetic field B = .5 t²

Flux Φ perpendicular to plane passing through it.= nBA sin30

rate of change of flux

dΦ/dt = nAdBsin30 / dt

= nA d/dt (.5t²x .5 )

= nA x 2 x .25 x t

At t = 4s

dΦ/dt = nA x 2

= 5x .01 x 2

= .1

current = induced emf / resistance

= .1 / 4

= .025 A

= 25 mA.

4 0

2 years ago

When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their

AysviL [449]

Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

$F = qvB$

Now this causes a centripetal acceleration

$F = = mv^2/r$

$qvB = mv^2/r$ ...........(i)

$B = mv/(rq)$ ...............(ii)

If accelerating potential V is same and then kinetic energy equals the potential energy difference

$\frac{1}{2} mv^2 = Vq$

$v = \sqrt{(2Vq/m)}$ put these value in equation (ii)

$B = m\frac{\sqrt{(2Vq/m)} }{rq}$

simplifying we get

$B =m \frac{(\sqrt{ 2Vm/q})}{r}$

for same location r will be same in both case

$B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}$ ..............(iii)

$B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}$ ..........(iv)

dividing (iv) and (iii) equation we get

$\frac{B_{10}}{B_{7}} = \sqrt{\frac{m_{10}}{{m_7}} }$

${B_{10}} = B_{7} \sqrt{\frac{m_{10}}{{m_7}} }$

$B_{10} = 0.2574T\sqrt{\frac{ (1.663x10^-26}{(1.165x10^-26)}$

so on solving we get

=0.3075 T

5 0

2 years ago

Help please. what is the formula BaF2 tells you about this element

nataly862011 [7]

Barium fluoride(BaF2) is a chemical compound of barium and fluorine and is a salt. It is a solid which can be a transparent crystal.

3 0

3 years ago

Please Help!

irga5000 [103]

The maximum force that the tires can exert on the road before slipping is 16200 N.

From the information in the question;

The coefficient of static friction = 0.9

The mass of the car = 1800 kg

Using the formula;

μ = F/R

μ = coefficient of static friction

F = force on the tires

R = the reaction force

But recall that the reaction is equal in magnitude to the weight of the car.

W=R

Hence; R = 1800 kg × 10 ms-2 = 18000 N

Making F the subject of the formula;

F = μR

Substituting values;

F = 18000 N × 0.9

F = 16200 N

Hence, the maximum force that the tires can exert on the road before slipping is 16200 N.

Learn more: brainly.com/question/18754989

6 0

2 years ago

When electrons are lost, a ______ ion is formed. When electrons are gained, a __________ ion is formed.

When electrons are lost, a ion is formed. When electrons are gained, a ____ ion is formed.