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arlik [135]
3 years ago
12

An aircraft, traveling northward, lands on a runway with a speed of 77 m/s. Once it touches down, it slows to 6.3 m/s over 705 m

of runway. What is the average acceleration (magnitude and direction) of the plane during landing (in m/s2)
Physics
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

magnitude

a = 4.18 m/s^2

Direction

Opposite to the velocity of aircraft

Explanation:

As we know that the initial speed of the aircraft when it land on the ground is

v_i = 77 m/s

now the final speed of the aircraft when it covers 705 m on runway is given as

v_f = 6.3 m/s

so here we know that

v_f^2 - v_i^2 = 2 a d

so now we can say that

6.3^2 - 77^2 = 2ad

6.3^2 - 77^2 = 2(a)(705)

a = -4.18 m/s^2

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Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha
ikadub [295]

We have that the spring constant is mathematically given as

k=2.37*10^{11}N/m

Generally, the equation for angular velocity is mathematically given by

\omega=\sqrt{k}{m}

Where

k=spring constant

And

\omega =\frac{2\pi}{T}

Therefore

\frac{2\pi}{T}=\sqrt{k}{n}

Hence giving spring constant k

k=m((\frac{2 \pi}{T})^2

Generally

Mass of earth m=5.97*10^{24}

Period for on complete resolution of Earth around the Sun

T=365 days

T=365*24*3600

Therefore

k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2

k=2.37*10^{11}N/m

In conclusion

The effective spring constant of this simple harmonic motion is

k=2.37*10^{11}N/m

For more information on this visit

brainly.com/question/14159361

8 0
3 years ago
Find the resistance of a stereo: current is 7 A voltage is 49 V.
pochemuha

Answer:

R = 7 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.

V = I*R

where:

V = voltage = 49 [V] (units of volts)

I = current = 7 [amp] (amperes)

R = resistance [ohms]

Now clearing R.

R =V/I

R = 49/7

R = 7 [amp]

5 0
3 years ago
What is the momentum of a 8 kilogram cart moving with a speed of 12 meters per<br> second?
lisov135 [29]

Answer:

Explanation:

momentum = mv

m = 8 kg

v = 12 m/s

momentum = 8 * 12 = 96 kg m/s

5 0
2 years ago
In a system with only a single force acting upon a body, what is the relationship between the change in kinetic energy and the w
Makovka662 [10]

Answer: W.D = 1/2mv^2

Explanation:

If an external force or a single force is acting on a body. Just like the first law of thermodynamics, the force acting on the body will cause work done on the system.

Work done = force × distance

And the work done on the body will cause the molecules of the body to experience motion and thereby producing kinetic energy.

The work done will be converted to kinetic energy.

W.D = 1/2mv^2

6 0
3 years ago
36. The top floor of a building is 20 m above the basement. Show that the water pressure in the basement is nearly 200 kPa great
blagie [28]

Explanation:

pressure=density of water × gravity ×height

=1000×9.8×20=196,000N/m^2

=196000/1000=196kpa which is almost 200kpa

8 0
2 years ago
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