Question

An aircraft, traveling northward, lands on a runway with a speed of 77 m/s. Once it touches down, it slows to 6.3 m/s over 705 m of runway. What is the average acceleration (magnitude and direction) of the plane during landing (in m/s2)

Answer 1

Answer:

magnitude

$a = 4.18 m/s^2$

Direction

Opposite to the velocity of aircraft

Explanation:

As we know that the initial speed of the aircraft when it land on the ground is

$v_i = 77 m/s$

now the final speed of the aircraft when it covers 705 m on runway is given as

$v_f = 6.3 m/s$

so here we know that

$v_f^2 - v_i^2 = 2 a d$

so now we can say that

$6.3^2 - 77^2 = 2ad$

$6.3^2 - 77^2 = 2(a)(705)$

$a = -4.18 m/s^2$