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I am Lyosha [343]
3 years ago
8

Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the ap

erture. The diameter of the central bright area is 5.4 cm. What is the diameter of the aperture?
Physics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

The answer is "1.144 \times 10^{-4} \ m".

Explanation:

w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\

   =\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m

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Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

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(a) We know that,

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At t = 1 s

v=20\ cos2-30\ sin2

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We know that,

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a=\dfrac{d(20\ cos2-30\ sin2)}{dt}

a=-40\ cos2t-60\ cos2t

At t = 1 s

v=-40\ cos2-60\ cos2

a=-99.93\ mm/s^2

(b) For maximum velocity, \dfrac{dv}{dt}=a=0

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4 years ago
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Answer:

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