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I am Lyosha [343]
3 years ago
8

Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the ap

erture. The diameter of the central bright area is 5.4 cm. What is the diameter of the aperture?
Physics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

The answer is "1.144 \times 10^{-4} \ m".

Explanation:

w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\

   =\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m

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Answer:

The correct option is;

(c) 64W

Explanation:

Here we have the Coefficient Of Performance, COP given by

COP = \frac{Q_{cold}}{W} = 3.1

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Q_{cold} = m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J

Therefore, plugging in the value for  Q_{cold} in the COP equation we get;

COP = \frac{197.39 }{W} = 3.1 which gives

W =  \frac{197.39 }{3.1} = 63.674 \ J

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