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grandymaker [24]
3 years ago
10

A proton of mass 1.67×10-27 kg is being accelerated along a straight line at 7.01×1015 m/s2 in an accelerator. If the proton has

an initial speed of 6.63×107 m/s and travels 3.63 cm, what then is its speed?
Physics
1 answer:
Masja [62]3 years ago
5 0

Answer:

v_f=7*10^7\frac{m}{s}

Explanation:

The proton is under a linear motion with constant acceleration. So, we use the kinemtic equations to calculate its final speed. We know its acceleration, its initial speed and its traveled distance. Thus, we use the following equation:

v_f^2=v_0^2+2ax\\v_f=\sqrt{v_0^2+2ax}\\v_f=\sqrt{(6.63*10^7\frac{m}{s})^2+2(7.01*10^{15}\frac{m}{s^2})(3.63*10^{-2}m)}\\v_f=7*10^7\frac{m}{s}

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grin007 [14]
I’ve got 120 n, hope it helps!

7 0
2 years ago
Must physics always be explained by math?
cluponka [151]

Answer:

Because Physics is mainly composited of math

Explanation:

If you really think about it the only way any science works is off maths, whether that be measuring the amount of NaOH to put into a solution or determening the amount of sugar you want in a cake it all relys on maths

5 0
3 years ago
( 8c5p79) A certain force gives mass m1 an acceleration of 13.5 m/s2 and mass m2 an acceleration of 3.5 m/s2. What acceleration
Talja [164]

Answer:

4.725 m/s^{2}

Explanation:

We know that from Newton's second law of motion, F=ma hence making acceleration the subject then a=\frac {F}{m}  where a is acceleration, F is force and m is mass

Also making mass the subject of the formula m=\frac {F}{a}

For m1= \frac {F}{13.5} and m2=\frac {F}{3.5} hence F=(m2-m1)a= (\frac {F}{3.5}-\frac {F}{13.5})a=0.2116402116\\\frac {1}{a}=0.2116402116\\a=4.725 m/s^{2}

4 0
2 years ago
3 light-years =________.
KATRIN_1 [288]

               ( 3 yr) · (186,282.397 mile/s) · (86,400 s/day) · (365 day/yr)

           =  (3 · 186,282.397 · 86,400 · 365)  mile

           =      1.762380502 x 10¹³  miles

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6 0
3 years ago
Which of the following is a false statement? Select one:
Art [367]

Answer:

The false statement is in option 'd': The center of mass of an object must lie within the object.

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Center of mass is a theoretical point in a system of particles where the whole mass of the system is assumed to be concentrated.

Mathematically the position vector of center of mass is defined as

\overrightarrow{r}_{com}=\int \overrightarrow{r}_{i}dm

where,

\overrightarrow{r}_{i} is the position vector of the mass dm.

As we can see for homogenous symmetrical objects such as a sphere,cube,disc the center of mass is located at the centroid of the shapes itself but in many shapes it is located outside the body also.

Examples of shapes in which center of mass is located outside the body:

1) Horseshoe shaped body.

2) A thin ring.

In many cases we can make shapes of bodies whose center of mass lies outside the body.

6 0
2 years ago
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