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grandymaker [24]

3 years ago

10

A proton of mass 1.67×10-27 kg is being accelerated along a straight line at 7.01×1015 m/s2 in an accelerator. If the proton has

an initial speed of 6.63×107 m/s and travels 3.63 cm, what then is its speed?

1 answer:

Masja [62]3 years ago

5 0

Answer:

$v_f=7*10^7\frac{m}{s}$

Explanation:

The proton is under a linear motion with constant acceleration. So, we use the kinemtic equations to calculate its final speed. We know its acceleration, its initial speed and its traveled distance. Thus, we use the following equation:

$v_f^2=v_0^2+2ax\\v_f=\sqrt{v_0^2+2ax}\\v_f=\sqrt{(6.63*10^7\frac{m}{s})^2+2(7.01*10^{15}\frac{m}{s^2})(3.63*10^{-2}m)}\\v_f=7*10^7\frac{m}{s}$

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Assessing and monitoring your fluid levels will help you optimize your car's _______.

juin [17]

Answer:

A. fuel mileage and longevity

Explanation:

For a person purchasing a car, car longevity is one of the main concern. They are also interested in many things such as maximum mileage and service life.

By properly monitoring and assessing few measures one can maintain the efficiency and longevity of the car. One such thing is by monitoring the liquid levels of the car. Certain liquids like the coolant or radiator water level should be well maintain in proper level in order to run the car economically.

Thus by doing this, one can optimize the car's longevity and the fuel mileage.

Hence the correct option is (A).

3 0

3 years ago

Determine the components of reaction at the fixed support

denis-greek [22]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The components of reaction at the fixed support are

$A_{(x)} = 400 \ N$ , $A_{(y)} = -500 \ N$ , $A_{(z)} = 600 \ N$ , $M_x = 1225 \ N\cdot m$ , $M_y = 750 \ N\cdot m$ , $M_z = 0 \ N\cdot m$

Explanation:

Looking at the diagram uploaded we see that there are two forces acting along the x-axis on the fixed support

These force are 400 N and $A_{(x)}$ [ i.e the reactive force of 400 N ]

Hence the sum of forces along the x axis is mathematically represented as

$A_{(x)} - 400 = 0$

=> $A_{(x)} = 400 \ N$

Looking at the diagram uploaded we see that there are two forces acting along the y-axis on the fixed support

These force are 500 N and $A_{(y)}$ [ i.e the force acting along the same direction with 500 N ]

Hence the sum of forces along the x axis is mathematically represented as

$A_{(y)} + 500 = 0$

=> $A_{(y)} = -500 \ N$

Looking at the diagram uploaded we see that there are two forces acting along the z-axis on the fixed support

These force are 600 N and $A_{(z)}$ [ i.e the reactive force of 600 N ]

Hence the sum of forces along the x axis is mathematically represented as

$A_{(z)} - 600 = 0$

=> $A_{(z)} = 600 \ N$

Generally taking moment about A along the x-axis we have that

$\sum M_x = M_x - 500 (0.75 + 0.5) + 600 ( 1 ) = 0$

=> $M_x = 1225 \ N\cdot m$

Generally taking moment about A along the y-axis we have that

$\sum M_y = M_y - 400 (0.75 ) + 600 ( 0.75 ) = 0$

=> $M_y = 750 \ N\cdot m$

Generally taking moment about A along the z-axis we have that

$\sum M_z = M_z = 0$

=> $M_z = 0 \ N\cdot m$

8 0

3 years ago

Please Help Quick ASAp Hurry

mamaluj [8]

Answer:

it maybe correct

Explanation:

You can feel an increase of pressure on your eardrums. ... The deeper you go under the sea, the greater the pressure of the water pushing down on you

5 0

3 years ago

Select the correct answer. Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 ne

sergiy2304 [10]

Acceleration of the table: B. 0.50 meters/second2

Explanation:

The problem can be solved by using Newton's second law of motion, which states that the net force acting on an object is the product of its mass and its acceleration. Mathematically:

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

For the table in this problem, we have:

$\sum F = 125 N - 120 N = 5 N$ is the net force on the table, because there are two forces of 125 N and 120 N acting in opposite directions

m = 10.0 kg is the mass of the table

Solving for a, we find the acceleration:

$a=\frac{\sum F}{m}=\frac{5}{10.0}=0.50 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

7 0

3 years ago

Read 2 more answers

A tennis player player receives a shot with the ball (.06kg) travelling horizontally at 50.0 m/s and returns the shot with the b

ahrayia [7]

Let:

<span>m- 0.0600Kg </span>
<span>v1- +50.0 m/s </span>
<span>v2- -42 m/s </span>

<span>a) </span>

<span>momentum1 - momentum2 = impulse </span>
<span>p1 - p2 = Ft </span>
<span>m(v1 + v2) = Ft </span>
<span>Ft = 0.54 N-s </span>

<span>b) </span>

<span>Work is traditionally force times distance but an easy way to get through this one is to think logically and keep your units straight: </span>

<span>The racket creates an overall velocity of 90 m/s for the ball: </span>

<span>W=(Ft)*(V) </span>
<span>W=0.54 N-s * 90 m/s </span>
<span>W=48.6 N-m = 48.6 J</span>

3 0

3 years ago