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astra-53 [7]
3 years ago
7

It’s science, the subject is light and color

Chemistry
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

22)convex

23)sun (sunlight reflect of the off the surface of the moon

24)because of the way the atmosphere interacts with sunlight

25) transparent : glass,contact lenses,water,air

translucent: wax paper, oil paper, thin sheets

opaque : plastic, wood, leather

26)when light react with opaque: none of it passes though

when it reacts with transparent : it passes through

when it react with translucent : only some of it passes through, the light does not pass directly through the material

Explanation:

24 blue light is scattered in all directions by the tiny molecules of air in earth's atmosphere

You might be interested in
Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car
jarptica [38.1K]

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

<em>Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.</em>

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

<em>Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). </em>Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = <em>84.7g de CaCO₃</em>

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100<em> = </em>

<h3>67.8%</h3>
7 0
3 years ago
An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder
seraphim [82]

Answer:

\Delta H=-11897J

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

\Delta H=\Delta U+V\Delta P

Whereas the change in the internal energy is computed by:

\Delta U=nCv\Delta T

So we compute the initial and final temperatures for one mole of the ideal gas:

T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K  }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K  }{n}

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J

Then, the volume-pressure product in Joules:

V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J

Finally, the change in the enthalpy for the process:

\Delta H=-7140J-4757J\\\\\Delta H=-11897J

Best regards.

7 0
3 years ago
Whatvdo you meant by acid and base​
larisa86 [58]

Answer:

e meri a

Explanation:

Application software is a software which performs special task for user

3 0
3 years ago
Read 2 more answers
What is the difference between autotrophs and heterotroph
IRISSAK [1]
Are there any choices for anwsers

4 0
3 years ago
at its discovery, benzene was recognized to be a unique unsaturated hydrocarbon. this was because it either failed to react, or
Bingel [31]

At its discovery, benzene was recognized to be a unique unsaturated hydrocarbon because it either failed to react, by substitution with common reagents or reacted by addition that led to reactions with alkenes.

<h3>What are unsaturated hydrocarbons?</h3>

Unsaturated hydrocarbons are the hydrocarbons which have at least on double or triple carbon to carbon bond in its molecules.

All other hydrocarbons are unsaturated except for the alkanes and the cyclic alkanes.

Benzene is an aromatic compound which has a special six-carbon ring with are resonance structure reflecting the presence of three carbon-carbon bonds in its molecules.

The common reactions of unsaturated hydrocarbons are substitution and addition reactions.

However, benzene on its discovery did not undergo any of these reactions.

In conclusion, benzene showed a difference when compared with the common unsaturated hydrocarbons as it did not undergo either substitution or addition reactions.

Learn more about benzene at: brainly.com/question/6028840

#SPJ1

6 0
1 year ago
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