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4 years ago

O2 + C3H2 + H2O + CO2 Reaction type?

Chemistry

1 answer:

Kobotan [32]4 years ago

3 0

Answer:

Combustion is the reaction type if you meant to put a "=" in between C3H2 and H2O

You might be interested in

What kind of bond is created by a week electrical attraction between polar molecules

Studentka2010 [4]

Answer : The dipole-dipole interaction.

Explanation : The kind of bond that is created by a weak electrical attraction between two polar molecules is dipole-dipole interaction.

The type of force which occurs between the positive end of one molecule and the negative end of another molecule: is dipole-dipole interaction.

For better understanding, please refer the attachment.

8 0

3 years ago

Calculate the enthalpy change (∆H) for the reaction- N2(g) + 3 F2(g) –––> 2 NF3(g) given the following bond enthalpies: N≡N 9

Natali5045456 [20]

Answer:

– 844 kJ/mol.

Explanation:

The following data were obtained from the question:

N2(g) + 3 F2(g) –––> 2 NF3(g)

Enthalpy of N≡N (N2) = 945 kJ/mol

Enthalpy of F–F (F2) = 155 kJ/mol

Enthalpy of N–F3 (NF3) = 283 kJ/mol

Enthalpy change (∆H) =?

Next, we shall determine the enthalpy of reactant.

This is illustrated below:

Enthalpy of reactant (Hr) = 945 + 3(155)

Enthalpy of reactant (Hr) = 945 + 465

Enthalpy of reactant (Hr) = 1410 kJ/mol

Next, we shall determine the enthalpy of the product.

This is illustrated below:

Enthalpy of product (Hp) = 2 x 283

Enthalpy of product (Hp) = 566 kJ/mol

Finally, we shall determine the enthalpy change (∆H) for the reaction as follow:

Enthalpy of reactant (Hr) = 1410 kJ/mol

Enthalpy of product (Hp) = 566 kJ/mol

Enthalpy change (∆H) =?

Enthalpy change (∆H) = Enthalpy of product (Hp) – Enthalpy of reactant (Hr)

Enthalpy change (∆H) = 566 – 1410

Enthalpy change (∆H) = – 844 kJ/mol

7 0

3 years ago

Que órgano del sistema digestivo almacena bilis

lara [203]

Answer:

Gallbladder

Explanation:

4 0

3 years ago

A home gets its water from a private well which of the following is a sign that the water quality maybe low

Natali [406]

Your answer would probably be D!

6 0

3 years ago

URGENT!??! Please hurry ?!!!

Montano1993 [528]

Answer:

Table which was completed correctly is :

B) Answer choice G

Explanation:

Metals : Most of the elements in the periodic comes in the category of metal. They are found in left and middle of periodic table.

List of metals

Alkali : Li , Na , K ,Rb , Cs ,Fr

Alkaline : Be , Mg , Ca , Sr ,Ba ,Ra

Transition : Sc ,Ti ,V ,Cr ,Mn , Fe , Co, Ni Cu , Zn ,Y ,Zr ,Nb ,Mo ,Tc ,Ru , Rh , Pd , Ag , Cd , In , Sn, La ,Hf ,Ta ,W ,Re ,Os ,Ir ,Pt ,Au ,Hg

Non -Metals: Most of the p-block element are non metal. They are present in upper - right corner of the periodic table.

Non - metals : H , He , C ,N , O , F ,P ,S , Cl, Ar , Br , Xe ,At ,Rn,

Metalloid : They show properties of both the metals and the non - metals.

Also called as semimetals

Metalloid : B ,Si ,Ge ,As ,Sb ,Te ,Po

In table F :

B = metalloid , N = non metal ( wrong-match) , Ra = metal ( wrong-match) , He = Non - metal ( wrong-match)

In table G : Correctly matched

I = Non - metal , Ca = metal , Rb = metal , As = metalloid

In table H:

Ni = metal ( wrong-match) , C = metalloid ( wrong-match) , Mg = metal , Pb = Metal

In table J:

Cu = metal , Sb = Metalloid( wrong-match) , S = non metal( wrong-match) ,Ne = non metal

6 0

3 years ago