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Mandarinka [93]
3 years ago
7

Consider a metal ion with the outer electron configuration of d^4. In a coordination complex, the number of unpaired electrons i

n that metal ion depends on the orientation and type of ligands that surround it. Classify each description of a complex by the number of unpaired electrons in the d^4 metal ion.
Chemistry
1 answer:
yarga [219]3 years ago
6 0

Answer:                                                                        

a) 0

b) 4

c) 4

d) 4

e) 2

f) 4

<u>Explanation:                                                                  No. unpaired electrons:</u>

a) square planar, strong field                                                      

        d⁴                                                                                                 0

b) tetrahedral, strong field

        d⁴                                                                                                   4                                                      

c) Octahedral, weak field

       d⁴                                                                                                    4

d) square planar, weak field

      d⁴                                                                                                      4

e) Octahedral, strong field

      d⁴                                                                                                      2

f) tetrahedral, weak field

     d⁴                                                                                                       4

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A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
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19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

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Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

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Explanation:

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