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german
3 years ago
8

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

ivides into two cells every 20 minutes. The initial population of a culture is 58 cells. (a) Find the relative growth rate. (Assume t is measured in hours.) k = Correct: Your answer is correct. (b) Find an expression for the number of cells after t hours. P(t) = Correct: Your answer is correct. (c) Find the number of cells after 8 hours. 973078528 Correct: Your answer is correct. cells (d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.) billion cells per hour (e) When will the population reach 20,000 cells? (Round your answer to two decimal places.) 2.81 Correct: Your answer is correct. hr
Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

The E. Coli will grow at a rate of approximately 800% an hour.

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Step-by-step explanation:

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Which of the lines is perpendicular to the line shown in the graph
Nitella [24]

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The line passing through (-8, 10) and (-1, 4).

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3 years ago
What is 999 times 100.0​
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99,900

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3 years ago
Read 2 more answers
What is the variable of p and k explain please
scoundrel [369]
For the P=-4
what you do is subtracting 6 to the 38 you will have -8p=32 then you will divide-8 to both sides and your answer will be p=-4
check 6-8(-4)=38
6+32=38
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i got K=5.6
what you do is add 13 to the 15 and you will have 28=5k then you will divide 5 to both sides and you will have k=5.6
check 15=5(5.6)-13
15=28-13
15=15
3 0
3 years ago
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