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german
3 years ago
8

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

ivides into two cells every 20 minutes. The initial population of a culture is 58 cells. (a) Find the relative growth rate. (Assume t is measured in hours.) k = Correct: Your answer is correct. (b) Find an expression for the number of cells after t hours. P(t) = Correct: Your answer is correct. (c) Find the number of cells after 8 hours. 973078528 Correct: Your answer is correct. cells (d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.) billion cells per hour (e) When will the population reach 20,000 cells? (Round your answer to two decimal places.) 2.81 Correct: Your answer is correct. hr
Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

The E. Coli will grow at a rate of approximately 800% an hour.

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Answer:

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General Formulas and Concepts:

<u>Calculus</u>

  • Limit Properties: \lim_{n \to a} c = c
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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x + 2

<u>Step 2: Find derivative</u>

  1. Substitute:                         f'(x)= \lim_{h \to 0} \frac{((x + h) + 2)-(x+2)}{h}
  2. Distribute:                          f'(x)= \lim_{h \to 0} \frac{x + h + 2-x-2}{h}
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