Answer:
Yes
Explanation:
The speed of light when it travels through glass, diamond, etc, the light travels at different speed from the speed of light. Speed of the light in material is related to the index of refraction.
The change in speed which occurs when the light passes from one medium to the another is responsible for bending of the light which is called as refraction.
<u>When the light goes into a medium with the higher index of the refraction, light bends towards normal. Conversely, if the light traveling goes from higher refractive index to lower refractive index, it will bend away from the normal.
</u>
<u>Hence, the refraction is different in both the scenario.</u>
Answer: Dust released in the air could be radioactive.
Explanation:
Uranium is a radioactive element. It decays naturally to attain stability. While mining, the dust displaces into the air causing not only harm to environment but for the workers as well. The released in the air could be radioactive which would be inhaled posing threat for lung cancer.
Thus, the correct answer is dust released in the air could be radioactive is a concern about mining Uranium.
Potential Energy (P.E) = Mass x
Acceleration due to Gravity x Altitude. Putting this value in the above equation we get, Dimensional Formula of
Potential energy= M1L2T-2.
The second statement is false. The Sun is a star, but not the only star.
Explanation:
Gauss Law relates the distribution of electric charge to the resulting electric field.
Applying Gauss's Law,
EA = Q / ε₀
Where:
E is the magnitude of the electric field,
A is the cross-sectional area of the conducting sphere,
Q is the positive charge
ε₀ is the permittivity
We be considering cases for the specified regions.
<u>Case 1</u>: When r < R
The electric field is zero, since the enclosed charge is equal to zero
E(r) = 0
<u>Case 2</u>: When R < r < 2R
The enclosed charge equals to Q, then the electric field equals;
E(4πr²) = Q / ε₀
E = Q / 4πε₀r²
E = KQ /r²
Constant K = 1 / 4πε₀ = 9.0 × 10⁹ Nm²/C²
<u>Case 3</u>: When r > 2R
The enclosed charge equals to Q, then the electric field equals;
E(4πr²) = 2Q / ε₀
E = 2Q / 4πε₀r²
E = 2KQ /r²
