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san4es73 [151]
2 years ago
10

In a collision, the human body will strike the seatbelt, steering wheel, dash or windshield at? Group of answer choices only 10

to 15 miles per hour the same speed as the vehicle twice the speed of the vehicle one half the speed of the vehicle
Physics
2 answers:
Alla [95]2 years ago
3 0

Answer:

isn't this kinda like math

Explanation:

mrs_skeptik [129]2 years ago
3 0

In a collision, the human body will strike the seatbelt, steering wheel, dash, or windshield at the same speed as the vehicle.

A collision is when one object comes in contact with another, leading to an abrupt and forceful impact. This means that a collision happens when one object hits another surface or object with an extreme impact that causes injuries or damages.

  • There are three theories of collision, among which the "human collision" is the second theory.
  • In this theory, the impact of a collision between the human body and the external surface happens after the collision occurs.
  • But the force of the impact remains the same, meaning the force with which the body hits the other surface is at the same speed as the vehicle prior to the collision.
  • This is because while the collision may have occurred, the body is still moving at the same speed as the vehicle, thereby resulting in the same speed of the vehicle as that of the force of impact.
  • So, the <u>human body will strike the external or opposite surface at the speed of the vehicle</u>.

Prior to a collision, the body inside the vehicle is moving at the speed of the vehicle. So, when a collision occurs, the <u>body continues to move with that speed</u> even though the vehicle may have halted. Thus, <em>the human body will strike at the same speed as the vehicle</em>.  

Learn more about collision here:

brainly.com/question/11610989

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White raven [17]

Answer:

a) 4.49Hz

b) 0.536kg

c) 2.57s

Explanation:

This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:

x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)

for some time t you have:

x=0.134m

v=-12.1m/s

a=-107m/s^2

If you divide the first equation and the third equation, you can calculate w:

\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}

with this value you can compute the frequency:

a)

f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz

b)

the mass of the block is given by the formula:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg

c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:

\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s

Finally, the amplitude is:

x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m

5 0
2 years ago
47. A car travels 85 km in the first half hour of a trip. The car continues to travel for 2 more hours and travels 200 km. What
Otrada [13]

Answer: 114 km/h

Explanation:

The formula for determining average speed is expressed as

Average speed = total distance/total time

The car travels 85 km in the first half hour of a trip. The car continues to travel for 2 more hours and travels 200 km. It means that the total distance that the car travels is

85 + 200 = 285 km

The total time spent by the car is

0.5 + 2 = 2.5 hours

Therefore,

Average speed = 285/2.5 = 114 km/h

3 0
3 years ago
For what absolute value of the phase angle does a source deliver 71 % of the maximum possible power to an RLC circuit
kherson [118]

Answer: the absolute value of the phase angle is 28°

Explanation:

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Also for average electric power in an AC circuit

P_avg = V_rms × I_rms × cos²∅ -------let this be equ 3

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so p_max replaces V_rms × I_rms in equation 3

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78/100 = cos²∅

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∅ = cos⁻¹ ( √(78/100))

∅ =  cos⁻¹ ( 0.8832)

∅ = 27.969 ≈ 28°

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2 years ago
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