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Harlamova29_29 [7]
4 years ago
12

A 58.1 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 48.3 kg boy stands at one end of the board.

He walks from one end of the board to the other end with a velocity of 1.69 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice? -1.69m/s
Physics
1 answer:
VLD [36.1K]4 years ago
4 0

Answer:

V = 1.41 m /s

Explanation:

Movement in both wood board and boy is created by internal forces . No horizontal external force acts on them . So conservation of momentum will apply on both of them for movement in horizontal direction.

Mass of wood board x velocity = mass of boy x velocity

58.1 x V = 48.3 x 1.69

V = 1.41 m /s

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In 1650, an individual calculated that the earth was about 6,000 years old. since then what has happened to scientists of the ea
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A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is
mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate =  150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

h= \frac{1}{2}at^2

h= \frac{1}{2}4.71\times4.96^2

h= 58.012 m

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4 0
4 years ago
A force of 1.00 x 10^2 pounds acts at an angle of 60.0° to the x-axis. (The force is accurate to 3 significant figures.) What ar
tamaranim1 [39]

Answer:

Fx= 50.0 Pounds : Components of the force along the x-axis

Fy= 86.6 Pounds : Component of the force along the y-axis

Explanation:

Conceptual Analysis

To find the components (Fx, Fy) of the total force (F), we apply the trigonometric concepts for a right triangle, where the perpendicular sides of the triangle are the components (Fx, Fy) of the force (F), the hypotenuse (h) is the magnitude of the total force F and β is the angle that forms the horizontal component with the hypotenuse.

Formulas

cos β : x/h  :    x: side adjacent to the β angle  h: hypotenuse  (1)

sin β = y/h  :    y: side opposite to the β angle  h: hypotenuse  (2)

Known Data

Known data

F= 1.00 * 10² pounds  = 100 pounds :  magnitude of total force

β =  60.0° to the x-axis. : Angle that forms the force with the x-axis

Problem Development

We apply the formula 1 to calculate horizontal component (Fx)

cos β :Fx/F

Fx= F cosβ  = 100*cos 60° = 50.0 Pounds

We apply the formula 2 to calculate vertical component (Fy)

sin β = Fy/F

Fy= F sinβ = 100*sin 60° = 86.6 Pounds

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4 years ago
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M= 4kg
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momentum = Mv
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12kgms-¹ = 4kg×v
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