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Maslowich
3 years ago
15

A ball is released from rest at a height of 10 m and falls freely to the

Physics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

The new kinetic energy would be 16 times greater than before.

Explanation:

Kinetic energy is found using this formula:

  • KE = 1/2mv²
  • where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)

We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.

The velocity just before the ball hits the ground can be found by the equation:

  • √(2gh)

Let's substitute h = 10 m and h = 40 m into this formula.

  • √(2g(10))
  • √(2g(40))

We can see that the velocity increases by a factor of 4 (10 m → 40 m).

Therefore, this means that the kinetic energy would also be increased by a factor of (4)² = 16. Thus, the answer is D) The new kinetic energy would be 16 times greater than before.

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Explanation:

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A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on
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Answer:

\huge\boxed{\sf F = 0.28\ N}

Explanation:

<h3>Given Data:</h3>

Mass = m = 68 kg

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<h3>Required:</h3>

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<h3>Formula to be used:</h3>

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<h3>Solution:</h3>

\displaystyle F = \frac{(68)(30)}{7200} \\\\F = \frac{2040}{7200} \\\\F = 0.28 N\\\\\rule[225]{225}{2}

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