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Maslowich
3 years ago
15

A ball is released from rest at a height of 10 m and falls freely to the

Physics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

The new kinetic energy would be 16 times greater than before.

Explanation:

Kinetic energy is found using this formula:

  • KE = 1/2mv²
  • where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)

We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.

The velocity just before the ball hits the ground can be found by the equation:

  • √(2gh)

Let's substitute h = 10 m and h = 40 m into this formula.

  • √(2g(10))
  • √(2g(40))

We can see that the velocity increases by a factor of 4 (10 m → 40 m).

Therefore, this means that the kinetic energy would also be increased by a factor of (4)² = 16. Thus, the answer is D) The new kinetic energy would be 16 times greater than before.

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Is the acceleration due to gravity in projectile motion always negative? please explain
umka21 [38]
Before you start working on any motion problem, YOU decide which direction you're going to call 'positive'. Everybody almost always calls UP positive, and the acceleration of gravity points down, so it winds up negative. But you could just as well call DOWN the positive direction. Then, the cannonball is fired with a negative vertical speed, and the acceleration of gravity eventually robs all of its negative speed, and makes it start falling in the positive direction. The whole thing is your choice.
3 0
3 years ago
A circular loop carrying a current of 1.6 A is oriented in a magnetic field of 0.30 T. The loop has an area of 0.14 m 2 and is m
konstantin123 [22]

Answer:

The torque on the loop is 2.4 \times 10^{-2} Nm

Explanation:

Given:

Current I = 1.6 A

Magnetic field B = 0.30 T

Area of loop A = 0.14 m^{2}

Angle between magnetic field and area vector \theta = 21°

Form the formula of  torque in case of magnetic field,

 г = MB \sin \theta

Where M = magnetic moment

  M = IA

 г = IAB \sin 21

 г = 1.6 \times 0.30 \times 0.14 \times 0.3583

 г =2.4 \times 10^{-2} Nm

Therefore, the torque on the loop is 2.4 \times 10^{-2} Nm

7 0
3 years ago
Mr.smith and his wife were trying to move their new chair. Mr. Smith pulls with a force of 30N while Mrs.Smith pushes with a for
luda_lava [24]

Answer:

55N

Explanation:

30N + 25N = 55N

7 0
3 years ago
Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.
Zielflug [23.3K]

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

F=6.00*10^{-6}N

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}

Substitute the given values

F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N

4 0
3 years ago
A bomb of mass 4 kg, initially at rest, explodes breaking into two fragments of 1 kg and 3 kg. Which one of the following statem
Kazeer [188]

Answer: The 1 kg fragment will have three times the speed of the 3kg fragment.

Explanation:Here for the bomb, its chemical energy gets converted into the mechanical energy.

According to the law of conservation of momentum, the two bodies will have equal momentum and to satisfy this condition the lighter mass will have the higher velocity.

∵ momentum, p = mass × velocity

∴The 1 kg fragment will have three times the speed of the 3kg fragment.

6 0
3 years ago
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