Ask question

Ask question

All categories

Anestetic [448]

3 years ago

15

Find the acceleration of a train whose speed increases from 7m/s to 17 m/s in 120s

1 answer:

Ksenya-84 [330]3 years ago

7 0

Initial speed of the train = 7 m/s
Final speed of the train = 17 m/s
Change of speed of the train = (17 - 7) m/s
   = 10 m/s
Time taken for the change of the speed of the train = 120 s
Then
Acceleration of the train = Change of speed of the train/Time taken for the change of speed
   = 10/120 m/s^2
   = 1/12 m/s^2
   = 0.083 m/s^2
So the acceleration of the train is 1/12 meter per second square or 0.083 m/s^2. I hope this is the answer you were looking for.

You might be interested in

The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make i

balandron [24]

Answer:

The answer is

<h2>84.9 kPa</h2>

Explanation:

Using Boyle's law to find the final pressure

That's

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

$P_2 = \frac{P_1V_1}{V_2}$

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

$P_2 = \frac{115000 \times 480}{650} = \frac{55200000}{650} \\ = 84923.076923...$

We have the final answer as

<h3>84.9 kPa</h3>

Hope this helps you

7 0

3 years ago

Kind of physical barrier

adoni [48]

Doors, walls, distance.

5 0

3 years ago

Which surface exhibits the highest albedo measurement

k0ka [10]

Fresh snow is the surface that exhibits the highest albedo measurement.

8 0

3 years ago

In which type of circuit does charge move in only one direction?

mihalych1998 [28]

Answer:

<h2>the ans...is dc circuit...</h2>

6 0

3 years ago

Read 2 more answers

A block oscillating on a spring has period T = 2.8 s . (Note: You do not know values for either m or k. Do not assume any partic

olasank [31]

Answer:

Part a)

T = 3.96 s

Part b)

T = 1.98 s

Part c)

T = 2.8 s

Explanation:

As we know that time period of spring block system is given as

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

Part a)

If the mass of the block attached is doubled

then we will have

$T' = 2\pi\sqrt{\frac{2m}{k}}$

$T' = \sqrt2 T$

$T' = 3.96 s$

Part b)

If the spring constant is doubled

then we have

$T' = 2\pi\sqrt{\frac{m}{2k}}$

$T' = \frac{T}{\sqrt2}$

$T' = 1.98 s$

Part c)

If the amplitude is halved but mass and spring constant will remain the same

so here we know that time period does not depends on Amplitude

so we will have

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

7 0

2 years ago