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amm1812
3 years ago
6

State whether the pH at the equivalence point in each of the following titrations is expected to be less than 7, equal to 7, or

greater than 7. a. Strong acid (e.g. HCl) with strong base (e.g. NaOH) b. Weak acid (e.g. acetic acid, CH3COOH) with strong base (e.g. NaO
Chemistry
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

A. equal to 7

B. greater than 7

Explanation:

a. Strong acid (e.g. HCl) with strong base (e.g. NaOH)

HCl + NaOH ⇒ NaCl + H₂O

The reaction of HCl and NaOH will form a neutral salt, NaCl. So, the pH at the equivalence point will be equal to 7.

b. Weak acid (e.g. acetic acid, CH₃COOH) with strong base (e.g. NaOH)

CH₃COOH + NaOH ⇒ CH₃COONa + H₂O

The reaction of CH₃COOH and NaOH will form a basic salt, CH₃COONa. So, the pH at the equivalence point will be greater than 7.

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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.
max2010maxim [7]

From the calculations, the pH of the buffer is 3.1.

<h3>What is the pH of the buffer solution?</h3>

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

Learn more about pH:brainly.com/question/5102027

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6 0
2 years ago
Your friend challenged you to a race you know in order to beat him you must run 15 meters within 20 seconds in the northern dire
Marat540 [252]

Answer:

.75 meter north

Explanation:

v = d/t

v = 15/20

v = .75

7 0
3 years ago
4. Consider the following data: Metal Mass (9 Cu Specilic Heat_Wg % Temperature, 0,900 0.285 these two metals are placed in cont
lana66690 [7]

The heat will flow from copper to aluminum because Cu is at higher temperature. The heat liberated is -7.60kJ

When two metals at different temperatures are kept in contact, heat flows from hotter metal to colder metal until thermal equilibrium is reached.

Here Copper is at a temperature of 60 degree Celsius and aluminum is at 40 degree Celsius. Thus, heat will flow from Cu to Al.

In order to calculate the amount of heat liberated following calculations are required.

m1=262 g

T1=87 oC

Cp=0.385 J/g oC

T2=11.8 oC

The heat liberated can be expressed as follows:

Q=mCp(T2-T1)

Q=262 g*0.385 J/goC(11.8-87)oC

Q=-7585 J

=-7.60kJ

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brainly.com/question/13439286

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4 0
1 year ago
How many moles of hydrogen are required to make 32 moles of water?
NNADVOKAT [17]
You multiply 32 by 2, since there are two hydrogens in every water molecule.
7 0
3 years ago
Read 2 more answers
Q4. The student started with 16.0 grams of NaCl, show the calculation for the percent error that
Vedmedyk [2.9K]

Answer:

72.6% Error

Explanation:

% error = \frac{Real-Measured}{Real} * 100

\frac{58.44-16}{58.44} *100= 72.6

58.44 is the weight of NaCl

5 0
3 years ago
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