If 2500 grams of H2SO4 react with excess NH3 according to the illustration, the amount of ammonium sulfate that can be produced would be 3,370.92 grams. If only 3100 grams of ammonium sulfate were produced, the percentage yield would be 91.96%.
<h3>Stoichiometric calculations</h3>
From the equation of the reaction:
2NH3(aq) + H2SO4(aq) → (NH4)2SO4(aq)
The mole ratio of H2SO4 and (NH4)2SO4 is 1:1
Mole of 2500 grams H2SO4 = 2500/98 = 25.51 moles
Equivalent mole of (NH4)2SO4 = 25.51 moles
Mass of 25.51 moles (NH4)2SO4 = 25.51 x 132.14 = 3,370.92 grams
If 3100 g of (NH4)2SO4 were actually produced, the percentage yield would be:
Percent yield = 3100/3370.92 x 100 = 91.96%
More on percent yield can be found here: brainly.com/question/17042787
