This is the derivitive of x
critical points are where the first derivitive is equal to 0 or where the derivitive doesn't exist
ok, it is 0 at x=0 and 2
so I is true but not II
the point of inflection is where the slope of the 1st derivitive=0
that is at x=1
so III is true
I and III
4th option
Answer:
Left: The substance is decreasing by 1/2 every 12 years
Right: The substance is decreasing by 5.61% each year
Step-by-step explanation:
exponential decay
A = P(1-r)ᵇⁿ, where A is the final amount, P is the initial amount, r is the rate decreased each time period, b is the number of years, and n is the number of times compounded each year
let's write each formula in terms of this
left:
f(t) = 600(1/2)^(t/12)
matching values up...
A = P(1-r)ᵇⁿ
A = f(t)
P = 600
1 - r = 1/2 -> r = 1/2
t/12 = bn -> b = number of years = t, so bn = b/12 -> n = 1/12. Thus, it is compounded 1/12 times each year, so it is compounded every t*12 = 12 years. If it was compounded each month, it would be compounded 12 times a year
Thus, this is decreasing by a rate of 1/2 each 12 years
right:
f(t) = 600(1-0.0561)^(t)
matching values up...
A = P(1-r)ᵇⁿ
A = f(t)
P = 600
1 - r = 1 - 0.0561 -> r = 0.0561 = 5.61%
t = bn -> b = number of years = t, so bn = b -> n = 1. Thus, it is compounded annually (1 time each year)
Thus, this is decreasing by a rate of 5.61% each year
Answer:
A = {MOPN, MPON, PMON, POMN}
Step-by-step explanation:
Everybody has already decided that Naim is the last skater, so we need to make sure the result is 'N' in each last position. As we can see all of them have this.
However, we just need to make sure that Oliver doesn't first, because even if they're attempting to decide, the question is calling for the inclusion in which "Oliver is the very first skater in the race."
A complement is all the NOT values in the package or set, so it cannot be either A = {OPMN, OMPN) or A = {MOPN,MPON, OPMN, POMN), since all of them have at minimum one case where 'O' is first.
A complement is ALL other values of the set, and it can not be A = {MOPN, PMON}, since only two possible values are included in that package or set
The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We need to apply elementary row operation -2R₂+3R₁ tothe matrix:
![A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%262%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiplying Row 2 with -2 and Row1 with 3 and adding,
-9 15 6
-16 2 -6
----------
-25 17 0
After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁
The required matrix is:
Keywords: Matrices, elementary row operation
Learn more about matrices at:
#learnwithBrainly
