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IrinaVladis [17]

2 years ago

8

Aluminum and copper are good ____ because they don't have a strong hold on valence electrons. * a. Insulators b. Transistors c.

Conductors d. Generators

1 answer:

SOVA2 [1]2 years ago

6 0

aluminum and copper are C.) conductors

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I need the correct answer for this question please

kirill115 [55]

Try C. a downward gravitational force exerted by Earth

7 0

2 years ago

A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th

shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

$F = ma$

$a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}$

Now, we can calculate the final speed of the crate at the end of 10.0 m:

$v_{f}^{2} = v_{0}^{2} + 2ad_{1}$

$v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s$

For the next 10.5 meters we have frictional force:

$F - F_{\mu} = ma$

$F - \mu mg = ma$

So, the acceleration is:

$a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}$

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

$v_{f}^{2} = v_{0}^{2} + 2ad_{2}$

$v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s$

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.

I hope it helps you!

7 0

2 years ago

4. A bullet of mass 30 g is fired from a rifle of mass 5kg at a speed of 259m/s.

Ostrovityanka [42]

Answer:

Rifle Momentum=7.77kg*m/s v'= 1.554 m/s

Explanation:

a) m1v1 + m2v2 = m1v1' + m2v2'

0+0 = 0.03*259 + P(rifle momentum)

solve for P

p= 7.77kg*m/s

b) 7.77= 5*v'

v'= 1.554 m/s

8 0

2 years ago

A student is taking an animal science and an astronomy class. In animal sciences, she learns that panthers are called jaguars an

stiv31 [10]

Answer: A Comet!!!!!!!

Explanation:

6 0

2 years ago

Read 2 more answers

Four uniform objects having the same mass and diameter are released simultaneously from rest at the same distance above the bott

Jet001 [13]

The one with the majority of its mass furthest away from its center will reach the bottom last. The thin walled cylinder has all of its mass at the edge of itself, meaning its mass is the furthest from its center. If we take a look at the solid cylinder, it has some mass at its edge, but it also has a lot of mass very close to its center so it will roll faster than the thin walled cylinder. And the thin walled cylinder will be slower than the normal hollow cylinder because even though the hole cylinder doesn't have any mass at its center it does have some mass closer to its center than the thin walled cylinder.

So the last one to reach the bottom is the thin walled cylinder.

8 0

2 years ago