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Y_Kistochka [10]
3 years ago
15

Ice floats in water at 0°C. Why is this an example of physical equilibrium? a)The system is closed; nothing leaves the system. b

)No new substances form when the water molecules change state. c)The forward and reverse processes occur at different rates.
Physics
1 answer:
svp [43]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

Physical equilibrium is defined as a system in which there will occur no change in the physical state of substance. For example, at zero degree celsius water is present in both liquid and solid state as follows.

      H_{2}O(l) \rightleftharpoons H_{2}O(s)

For a system to be present in physical equilibrium is as follows.

The system must be a closed system.

It should be dynamic in nature.

There will occur no change in measurable property along with change in time.

Thus, we can conclude that ice floats in water at 0^{o}C this an example of physical equilibrium because no new substances form when the water molecules change state.

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A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s. How lo
Arlecino [84]

Answer:

t = 4.08 s

R = 40.8 m

Explanation:

The question is asking us to solve for the time of flight and the range of the rock.

Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:

  • Δx = v_0 t + 1/2at²

We have these known variables:

  • (v_0)_y = 0 m/s
  • a_y = -9.8 m/s²
  • Δx_y = -20 m

And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.

  • -20 = 0t + 1/2(-9.8)t²
  • -20 = 1/2(-9.8)t²
  • -20 = -4.9t²
  • t = 4.08 sec

The time it takes for the rock to reach the ground is 4.08 seconds.

Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.

List out known variables:

  • v_0 = 10 m/s
  • t = 4.08 s
  • a_x = 0 m/s

We are trying to solve for:

  • Δx_x = ?

By using the same equation, we can plug these known values into it and solve for Δx.

  • Δx = 10 * 4.08 + 1/2(0)(4.08)²
  • Δx = 10 * 4.08
  • Δx = 40.8 m

The rock lands 40.8 m from the base of the cliff.

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