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Novosadov [1.4K]
3 years ago
5

Can someone help Plz

Chemistry
1 answer:
Marrrta [24]3 years ago
6 0

Answer: A. 1.60 liters

Explanation:

2Na_2O_2+2CO_2\rightarrow 2Na_2CO_3+O_2

As can be seen from the balanced chemical equation, 2 moles of CO_2 produce 1 mole of O_2.

According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.

Thus 2 moles of CO_2 occupies 22.4\times 2=44.8L at STP and produce 1 mole of O_2 i.e. 22.4 L

44.8 L of CO_2 will produce 22.4 L of O_2

Thus 3.20L of CO_2 will produce \frac{22.4}{44.8}\times 3.20=1.60L



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Answer:

0,218 moles

Explanation:

I will first explain how many liters is 256ml, that is 0,256 l.

because the m stands for milli which is a factor of 1000 -> (256 ml / 1000 = 0,256 l)

To calculate the amount of moles you multiply the volume with the concentration. So 0,256l x 0,855M = 0,218 moles.

5 0
2 years ago
What is the fourth quantum number of the 3p electron in aluminum,
jeka94

Explanation:

here's the answer to your question

8 0
3 years ago
A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1
Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

Replacing:

ΔU = 26920J + 41854J = <em>68774 J</em>

This energy is per g of n-hexane, now, per mole of n-hexane:

\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}= -<em>5,921x10⁶J/mol</em>

<em>-negative because the energy is produced-</em>

I hope it helps!

5 0
4 years ago
Read 2 more answers
2,6 -dimetil nonano<br> 4 etil-2,2dimetil-4-propo:0ctano
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Answer:

it will be 26 %t _4

Explanation:

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7 0
3 years ago
Calculate the wavelength of a photon of light having a frequency of 3.50 x 1015 Hz.
Aliun [14]

Answer:

Wavelength, \lambda=8.57\times 10^{-8}\ m

Explanation:

Given that,

Frequency, f=3.5\times 10^{15}\ Hz

We need to find the wavelength of a photon of light. The relation between frequency and wavelength is as follows :

c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.5\times 10^{15}}\\\\\lambda=8.57\times 10^{-8}\ m

So, the wavelength of the light is 8.57\times 10^{-8}\ m.

4 0
3 years ago
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