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Leno4ka [110]
3 years ago
7

As the vibration of molecules increases, the _____ of the substance increases.

Chemistry
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

Answer option D- all of the above

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A sample of hydrogen gas is found to be 8.50 L at a temperature of 38.0 C and a pressure of 725mm Hg. Find the volume at STP.
Vsevolod [243]
Temp must be Kelvin
38 C = <span> <span> <span> 311.15 </span> </span> </span> K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span> <span> <span> 7.1182746306 </span> </span> </span> Liters

The formula to use is:

Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)

6 0
3 years ago
Why reducing power of elements decrease, on moving from left to right in a period?
masya89 [10]
The atom or an ion which loses electron /electrons is called reducing agent.

Whole moving across a period from left to right metallic character decreases, therefore reducing power element decreases.
3 0
3 years ago
Uranium and ________ are needed to run a nuclear reactor.
Ede4ka [16]
Water.  The energy from the fission reaction is used to heat water.  The water vaporizes which causes pressure rise.  The pressure is used to drive a turbine which runs a generator.
I hope this helps.
7 0
3 years ago
20 ml of an approximately 10% aqueous solution ofethylamine, ch3ch2nh2, is titrated with 0.3000 maqueous hcl.which indicator wou
S_A_V [24]

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5 0
3 years ago
Two ice skaters push off against one another starting from a stationary position. The 45.0-kg skater acquires a speed of 0.375 m
zalisa [80]

Answer:

The speed of the 60.0 kg skater should be 0.281 m/s

Explanation:

<u>Step 1: </u>Data given

Mass of skater 1 = 45.0 kg

speed of skater 1 = 0.375 m/s

Mass of skater 2 = 60.0 kg

<u>Step 2:</u> Calculate the speed of skater 2

To solve this problem, we will use 'Conservation of momenton'. This means  the momentum before the push equals the momentum after.

momentum p = m*v

Momentum p(before) = momentum p(after)

m1*v1 = m2 * v2

⇒ with m1 = mass of skater 1 = 45.0 kg

⇒ with v1 = the velocity of skater 1 = 0.375 m/s

⇒ with m2 = the mass of skater 2 = 60.0 kg

⇒ with v2 = the velocity of skater 2 = TO BE DETERMINED

45.0 * 0.375 = 60.0 * v2

v2 = (45.0*0.375)/60

v2 = 0.281 m/s

The speed of the 60.0 kg skater should be 0.281 m/s

6 0
3 years ago
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