As the vibration of molecules increases, the ____

How important is economic in your everyday life

docker41 [41]

Answer:

it is mega important.

Explanation:

3 0

3 years ago

A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: $\displaystyle q = mc \triangle T$

m is mass (g)
c is specific heat capacity (J/g °C)
ΔT is the change in temperature

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate c: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$

∴ specific heat capacity c is equal to around 0.45 J/g °C.

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Topic: AP Chemistry

Unit: Thermodynamics

5 0

3 years ago

The equilibrium constant for the reaction: HCHO(g) ⇌ H2(g) + CO(g).

tiny-mole [99]

Answer:

K = [H2] [CO] / [HCHO]

Explanation:

HCHO(g) ⇌ H2(g) + CO(g)

We can obtain the expression for the equilibrium constant for the above equation as follow:

Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

Thus, the equilibrium constant, K for the above equation can be written as follow:

K = [H2] [CO] / [HCHO]

3 0

3 years ago

What are weak bonds that allow flexibility in an enzyme

34kurt

Enzymes are characterized to have weak bonds because their tertiary structure could easily bend and break because it will have to adjust to the shape of the substrate. It could be done via induced fitting or lock-and-key theory. These weak bonds are intermolecular forces like the London forces, electrostatic interactions and hydrogen bonding.

7 0

3 years ago

What should be the mole fraction of O2 in the gas mixture the diver breathes in order to have the same partial pressure of oxyge

Nutka1998 [239]

The question is incomplete, here is the complete question:

A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm.

What should be the mole fraction of $O_2$ in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? Note that the mole fraction of oxygen at sea level is 0.209.